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This is not a problem. You have the solution, just debug it until you get it right instead of asking for help.
Kuphryn
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Another solution to your problem is to replace all the carriage returns with nulls, then process the buffer as an array of zstrings.
*(cpBuffer + strlen(cpBuffer) + 1) = 0;
char *p = strchr(cpTheBuffer,'\r');
while (p && *p)
{
*p = 0;
p = strchr(p+1,'\r');
}
p = cpTheBuffer;
while (*p)
{
ProcessRecord(p);
p += strlen(p)+1;
}
onwards and upwards...
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Thanks basementman, good suggestion but have to actually extract the strings and display them individually.
Any other ideas??
thanks.
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In the ProcessRecord function described previously, you can do the same sort of logic with the comma field delimiters just as you have done with the record delimiters. As a matter of fact, you could use the same function (genericized, of course) to parse records and fields simply by parameterizing the delimiter character. You could also make it more robust by respecting the delimiters that appear in quoted strings, etc.
onwards and upwards...
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what does 0x0a mean in this context?
if (symbol == 0x0a)
count++;
Mark J Jackson
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0x0a is a hexadecimal number, the equivalent of 10 decimal.
--Mike--
"So where does that leave us? Well, it leaves us right back where we started, only more confused than before." -- Matt Gullett
Ericahist | Homepage | RightClick-Encrypt | 1ClickPicGrabber
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hi every one
I am new to MFC c++. Which books i should go for?
How to learn Win32 API's?????????
pl. help
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Your welcome
Regards,
Brian Dela 
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After you get a little familiar with MFC, definitely check out MFC Internals.
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Hi Gang,
I was just wondering if anybody has a vertically aligned Cedit control out there.
Thanks,
Nick
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Anybody know of a class to just validate an XML Document. I don't need to read or write to an XML file. Just validate it.
Any ideas?
Regards,
Brian Dela
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Brian,
The Xerces (XML4C) parser is small, fast and free. I chose it over (ugh) MSXML.
/ravi
Let's put "civil" back in "civilization"
Home | Articles | Freeware | Music
ravib@ravib.com
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What is 0x0a and 0x0d in programming? What does it do?
Mark J Jackson
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in what context ?
all alone like that, they are hex values
0x0a = 10 (decimal)
0x0d = 13 (decimal)
Maximilien Lincourt
For success one must aquire one's self
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that mean carriage return and line feed (\r and \n).
onwards and upwards...
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Hello,
I was just wondering if anyone else was getting this type of error.
Basically, in the last little while I have created my own versions of two common Windows controls and I would like to put them all in one project. My first control was a masked text box and everything work fine except that I would lose certain properties that I set in design after I compiled. For example, I had a "Mask Type" enum property that could be set at design time but when I ran the program and I went back to Visual Studio (while the program was still running) the "Masked Type" property would reset to its default state. The program ran properly the first time with the masked type but as soon as I closed it and ran it again, it would use the default value that it had been reset to. This problem frusterated me to no end as I couldn't do anything to save that property but I did narrow it down to that fact that it was because the property was an enum type. As a result, I found that if I moved that enum type to a different class, it would save properly and I could finally move on (although not as happily as I would have hoped). Recently, I have created a customized tab control that would allow me to change the style and colours of the pages. Again everything seemed to work fine but as I neared completion, I noticed that the design view was again not saving the changes that I was making in it after I had compiled. This time is was the pages collection that was losing its settings. Again, if I moved the collection outside of the class and into it's own class, the design time properties saved properly and I could use it normally.
My question is: Does anyone know what I am doing wrong (or possibly doing wrong) Has anyone had this problem with the designer and if so, how did you fix it. I would appreciate any and all help that I could get in this matter. Thanks in advance.
Cheers,
Mike
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Excuse me if this question is really basic, I'm pretty new to C++ programming --
What is the difference between these two ways of declaring the value of a char data type?
Method 1 --
char myvar[21] = "text";
Method 2 --
char myvar[21];
myvar[21] = "text";
The second method seems to cause problems with my compiler (Dev-C++) when used in certain situations. I sometimes receive the error "assignment to 'char' from 'const char *' lacks a cast."
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yashraj1215 wrote:
char myvar[21];
myvar[21] = "text";
The second method seems to cause problems with my compiler (Dev-C++) when used in certain situations.
It's actually problematic in all situations. What is says is that the 22nd "position" of myvar points to "text", but since myvar only has 21 characters (0-20) to begin with, whatever happens to follow myvar in memory is being stepped on.
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yashraj1215 wrote:
myvar[21] = "text";
this pasically is saying
put "text" into the myvar at position 22
Remember that char myvar[21] has 21 characters accessed by myvar[0] to myvar[20]
Hoep this helps.
Regards,
Brian Dela
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yashraj1215 wrote:
char myvar[21] = "text";
This means "myvar is an array of 21 chars, and initialize the first five elements to the characters 't' 'e' 'x' 't' '\0'"
yashraj1215 wrote:
char myvar[21];
myvar[21] = "text";
This is incorrect code, that's why it doesn't compile. It's trying to assign an array of characters to one element in a character array.
It is also overrunning the array bounds. The elements are myvar[0] thru myvar[20]. Storing something in myvar[21] will overwrite other data.
--Mike--
"So where does that leave us? Well, it leaves us right back where we started, only more confused than before." -- Matt Gullett
Ericahist | Homepage | RightClick-Encrypt | 1ClickPicGrabber
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I have successfully created a program to edit the value of a key in the registry... finally! However, I still have a few questions about my code.
The following is one of the lines in my code:
RegSetValueEx(hKey, TEXT("LegalNoticeCaption"), 0, REG_SZ, (LPBYTE) mycaption, 51);
I used this code to set the value of the LegalNoticeCaption key to the value of mycaption, a previously declared char.
Question 1 --
I do not understand what purpose "(LPBYTE)" serves in this code; the code will not compile without it. I found "(LPBYTE)" in the MSDN library, but it never explained what it does or what it means... does anyone know?
Question 2 --
The last parameter of the RegSetValueEx function is supposed to be the size of the buffer. Is the buffer size equal to one byte per character?
Question 3 --
What is the difference between a signed char, an unsigned char, and a char? What are their individual purposes?
Thanks for your help.
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I start with #3
#3 signed char and char are the same thing
unsigned char and BYTE are the same. char being an integer data type needs unsigned version.
#1 since unsigned char has smallest size(1 byte) it is usually used to pass data buffers
LPBYTE == unsigned char*
#2 this one is tricky
for strings its == sizeof(TCHAR) * strlen
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