ATL / WTL / STL

19-Mar-04 10:44

I do not get "New ATL Object" in the "Insert" menu in the VC++ 6.0 with windows XP home edition. Could anybody help in enabling the above option.

Thanks
Prakash

Steve S21-Mar-04 22:33

Steve S

21-Mar-04 22:33

Sounds like your project doesn't have ATL support.

Steve S

Steve S21-Mar-04 22:36

Steve S

21-Mar-04 22:36

OOPS. That wasn't finished...
As I was saying, it sounds like your project doesn't have ATL support.
If you create a new project using "ATL/COM AppWizard", does that project have "insert ATL Object" as an option?

I'm sure that it used to be the case that it would ask if you wanted to add ATL support if it didn't have it.

An alternative is that you have some of the project files (like the IDL, the main CPP file) read-only (source control?) and this is why you can't do it.

Steve S

Member 45284922-Mar-04 4:35

22-Mar-04 4:35

Thank you for your support.
No I am not getting "Insert ATL Object" when I build a project using ATL/COM wizard. I know there is a option when it shows all the controls in the New ATL object but some how I am not getting it.

Steve S23-Mar-04 21:46

Steve S

23-Mar-04 21:46

Which edition of VC++ 6.0 are you using?

Steve S

Member 45284924-Mar-04 3:06

24-Mar-04 3:06

I am using VC++ 6.0 Enterprise Edition.

Prakash

Member 45284922-Mar-04 4:29

dll export stl map which carries built in Objects

22-Mar-04 4:29

I have built the project with ATL-COM object wizard.

Owner-draw in listview

IMiracle19-Mar-04 2:40

IMiracle

19-Mar-04 2:40

I want to set items' color individually in listview. Then I declare my listview as CContainedWindowT<clistviewctrl>, and receive NM_CUSTOMDRAW. On CDDS_PREPAINT draw stage, I return CDRF_NOTIFYITEMDRAW. On CDDS_ITEMPREPAINT draw stage, I return CDRF_NOTIFYSUBITEMDRAW. But I cannot receive CDDS_ITEMPREPAINT|CDDS_SUBITEM draw stage! Some one help me.

skpanda17-Mar-04 23:45

skpanda

17-Mar-04 23:45

hello,
i have a problem.

i m creating a C++ regular DLL in which i used C++ STL class like map,list etc.

i have 3 classes in my module.now i m creating the dll.
i m storing the objects of a built in type class in the map
and i have to create the dll for that module .

next is i want to export the dll to the client along with the map which stores the userdefined object (not built in type remember). how can i export the dll as well as the map to the client so that the client application can assess the C++ regular dll.

remember i have to create a C++ regular dll.

class prototype.....

class A
{
int abc;
-------
-----
------
some functions
};

now the map of user defined class is declared as :

map m_mapofA

now i used this map variable and implemented some functions of class A.
now i created the DLL as regular dll of C++.

now my problem is how th export the userdefined map to the client as i m not able to do that...

NOTE : i HAVE TO use only MS - Visual C++ 7.0 compiler(.NET compiler)

how can i do that ???

please help in this regard

regards
skpanda

Re: dll export stl map which carries built in Objects

ian mariano18-Mar-04 4:16

ian mariano

18-Mar-04 4:16

See Exporting from a DLL Using __declspec(dllexport) for your DLL and Importing into an Application Using __declspec(dllimport) for your client applications.

You will have to use the same header defining the class so that both sides can utilize the class. Note, you don't have to share the class implementation, just the structure, i.e., your class implementation is in a .cpp source file not as inline bodies in the .h header file.

The alternative is to use COM or .NET, which you said you couldn't do, but both preclude having to distribute a header file with your dll for consumption.

Ian Mariano - http://www.ian-space.com/

"We are all wave equations in the information matrix of the universe" - me

STL string to _bstr_t conversion

Sandeep Kulkarni17-Mar-04 19:31

Sandeep Kulkarni

17-Mar-04 19:31

hi i have an STL string object, which has a NULL char in the MIDDLE. For ex:

#include<string>
using namespace std;
....
string str = "abcdefghijklmnopqrstuvwxyz";
str[11] = 0; // str.size() still equals 26

Now i want to convert this string to _bstr_t object, retaining the NULL char and the chars after that. I tried this:
_bstr_t bstr = str.c_str();
But only first 11 chars are being copied(till NULL char). Pls help
TIA

ian mariano18-Mar-04 4:21

ian mariano

18-Mar-04 4:21

Just replace all '\0' characters in your std::string with some token character which you can convert back once it's a BSTR. Remember BSTRings are 2 bytes wide in Unicode, so NULL is 0x0000.

Ian Mariano - http://www.ian-space.com/

"We are all wave equations in the information matrix of the universe" - me

Michael Dunn18-Mar-04 5:10

Michael Dunn

18-Mar-04 5:10

basic_string, by definition, does not allow embedded 0 characters. When you stick a 0 in yourself, you're breaking the semantics of basic_string, so anything after that is not guaranteed to work.
You'll need to copy the string manually.

--Mike--
Personal stuff:: Ericahist | Homepage
Shareware stuff:: 1ClickPicGrabber | RightClick-Encrypt
CP stuff:: CP SearchBar v2.0.2 | C++ Forum FAQ
----
If my rhyme was a drug, I'd sell it by the gram.

Nemanja Trifunovic18-Mar-04 5:19

Nemanja Trifunovic

18-Mar-04 5:19

Michael Dunn wrote:
basic_string, by definition, does not allow embedded 0 characters.

Where did you find this information? AFAIK, the C++ standard does not mention this, and the only function that would be affected by embedded 0 characters is c_str()

Michael Dunn18-Mar-04 19:45

Michael Dunn

18-Mar-04 19:45

hmm... That was just one of those things I saw in passing and it happened to stick in my memory. Of course, I can't find it now. Frown | :(

So I could be wrong, don't quote me (well, you already did... don't quote me elsewhere Wink | ;)

)

The closest I can find is this:

basic_string::c_str
const E *c_str() const;
The member function returns a pointer to a nonmodifiable C string constructed by adding a terminating null element (E(0)) to the controlled sequence. Calling any non-const member function for *this can invalidate the pointer.

That's one aspect that treats E(0) as special, E(0) being '\0' for character strings. Since the caller of c_str() can look for E(0) to mark the end of the returned string, an E(0) in the middle of the string also looks like the end.

--Mike--
Personal stuff:: Ericahist | Homepage
Shareware stuff:: 1ClickPicGrabber | RightClick-Encrypt
CP stuff:: CP SearchBar v2.0.2 | C++ Forum FAQ
----
Kosh reminded me of some of the prima-donna programmers I've worked with. Knew everything but when you asked them a question; never gave you a straight answer.
-- Michael P. Butler in the Lounge

Nemanja Trifunovic19-Mar-04 6:40

Nemanja Trifunovic

19-Mar-04 6:40

Yep, embedded zeros can screw c_str. However, I made this little experiment:

char buffer[] = {'h','e','l','l','o', 0, 'w', 'o', 'r', 'l', 'd'};
string s (buffer, sizeof(buffer));
cout << s << " length = " << s.length()<< endl;

And the output (VC 7.1) is:

hello world length = 11