How to Explore a directory that the directory have Space (Start Menu)?

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C#3.5

String path = @"C:\ProgramData\Microsoft\Windows\Start Menu\Program";
Process.Start (path, "*.lnk");

Posted 19-Oct-15 22:49pm

Nigol_Learner

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[no name] 20-Oct-15 5:00am

You can specify the path as you did it will open the directory specified.

What error you are getting.

Nigol_Learner 20-Oct-15 5:11am

This is the error I'm getting Bro......

An unhandled exception of type 'System.ComponentModel.Win32Exception' occurred in System.dll

Additional information: The system cannot find the file specified

2 solutions

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E.F. Nijboer · Answer 1 · 2015-10-19T23:14:00

Solution 1

The signature is: Process.Start (Filename, Arguments);
You are trying to start a directory with "*.lnk" as parameter. I don't think it will work. You could try something like this:

Process.Start(@"%windir%\explorer.exe", @"C:\ProgramData\Microsoft\Windows\Start Menu\Program");

Good luck!

Posted 19-Oct-15 23:14pm

E.F. Nijboer

v2

PANKAJMAURYA · Answer 2 · 2015-10-19T23:19:00

Solution 2

What are you passing in

Process.Start (path, "*.lnk");

in the Process.Start() method second parameter command line arguments.
In your case I think you need not to pass a command line argument. so leave it blank.

C#

String path = @"C:\ProgramData\Microsoft\Windows\Start Menu\Program";
Process.Start (path, "");

Posted 19-Oct-15 23:19pm

PANKAJMAURYA

Comments

Nigol_Learner 20-Oct-15 5:22am

Im So sorry to both of you Guys,,,,, Actually I Done Stupid Things....

@"C:\ProgramData\Microsoft\Windows\Start Menu\Program"

To

@"C:\ProgramData\Microsoft\Windows\Start Menu\Programs"

Missing S (Program to Programs)

[no name] 20-Oct-15 5:25am

Also need not to pass "*.lnk" as 2nd parameter in Process.Start() method.

Nigol_Learner 20-Oct-15 5:27am

Thanks Bro

[no name] 20-Oct-15 5:32am

Never mind. Is that Okay.