find missing hour and insert between

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my tabel name

---customer--
this contain "transaction_time" contain hour field

\\\\my sql

SQL

SELECT amountPaid,  HOUR(`transactionTime`) time_range
FROM `customer_bill`

GROUP BY HOUR(`transactionTime`)

////and my ans is

id | amount | time diff

1 | 200 | 6
2 | 234 | 8
3 | 234 | 9
4 | 349 | 10

////i want my ans and id is 1 to 100000 ////

id | amount | time diff

1 | 200 | 6
0 | 0 | 7------its missing hour
2 | 234 | 8
3 | 234 | 9
4 | 349 | 10

Posted 19-Nov-15 22:04pm

Member 12115149

Updated 19-Nov-15 23:34pm

Suvendu Shekhar Giri

v2

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Suvendu Shekhar Giri · Answer 1 · 2015-11-20T00:10:00

You can take help of CTE to do this.
I don't have much knowledge on MySQL but if you can translate T-SQL (SQL Server) to MySQL query then you can refer following T-SQL query -

SQL

DECLARE @tbl AS TABLE(n INT)

;WITH cte_demo(n) AS
(
    SELECT 1 AS n
        UNION ALL
    SELECT n + 1
        FROM cte_demo
        WHERE n < 1000
)
INSERT INTO @tbl SELECT * FROM cte_demo OPTION (MAXRECURSION 1000)


SELECT ISNULL(id,0) AS Id, ISNULL(amount,0) AS amount,ISNULL([time diff],n) 
FROM
(
	SELECT 1 id, 200 amount, 6 [time diff]
	UNION ALL
	SELECT 2 , 234 , 8
	UNION ALL
	SELECT 3 , 234 , 9
	UNION ALL
	SELECT 4 , 349 , 10
) t1
RIGHT JOIN @tbl t2 ON t2.n=t1.[time diff]

Hope, it helps :)

if you need further help please, let me know.