Could you help me solve this problem?

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C#

{
    int x,y;
    float z;
    printf("Write 2 integers: ");
    scanf("%d%d",&x,&y);

    switch (x && y)
    {
    case x+y>0 && x+y<=4:
        z = exp(x+y);
        printf("%f is an output.\n",z);
        break;
    
    
    case x+y==8 || x+y==10:
    z = (pow(x,2)+y)/(x-y);
    printf("%f is an output.\n",z);
    break;
    
    default:
        z = 0;
        printf("%f is an output.\n",z);
    }
    return 0;
}

What I have tried:

I tried to add If statement but i couldnt

Posted 12-Mar-16 1:07am

Prof Stat

Updated 12-Mar-16 7:13am

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OriginalGriff 12-Mar-16 7:15am

What problem?
All you have done is dumped your code on us, without telling use what it is supposed to do, much less what it does wrong!
What does it do that you didn't expect, or not do that you did?
How do you make it do it? What do you enter to cause the problem?
Use the "Improve question" widget to edit your question and provide better information.

Member 12378355we 12-Mar-16 13:14pm

#include<stdio.h>
main()
{
int x,y,w; //Just add another variable
float z;
printf("Write 2 integers: ");
scanf("%d%d",&x,&y);
if((x+y==8 || x+y==10)) w=1;
if(x+y>0 && x+y<=4) w=0;

switch (w)
{
case 0:
z = exp(x+y);
printf("%f is an output.\n",z);
break;

case 1 :
z = (pow(x,2)+y)/(x-y);
printf("%f is an output.\n",z);
break;

default:
z = 0;
printf("%f is an output.\n",z);
}
return 0;
}

I think you didn't mean any hard jargon.....with the code?

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Richard MacCutchan · Answer 1 · 2016-03-12T01:28:00

Your case statements are not valid. Cases use constant values, not expressions. Your code should look like:

C++

int x,y;
float z;
printf("Write 2 integers: ");
scanf("%d%d",&x,&y);

if (x+y>0 && x+y<=4)
{
    z = exp(x+y);
}
else if (x+y==8 || x+y==10)
{
    z = (pow(x,2)+y)/(x-y);
}
else
    z = 0;

// you only need one printf at the end to print the value of z.
printf("%f is an output.\n",z);

Patrice T · Answer 2 · 2016-03-12T05:47:00

Solution 1 gives you a probable correction of switch, but since you didn't tell us what it is supposed to do, we can't be sure.
Obviously, you don't know the usage of switch.
You should properly learn the language as soon as possible.
Advice:
- read language documentation, follow tutorials.
- The debugger is your friend. It will show you what your code is really doing.
Follow the execution step by step, inspect variables and you will see that there is a point where it stop doing what you expect.
Mastering Debugging in Visual Studio 2010 - A Beginner's Guide[^]
http://docs.oracle.com/javase/7/docs/technotes/tools/windows/jdb.html[^]
https://www.jetbrains.com/idea/help/debugging-your-first-java-application.html[^]

Member 12378355we · Answer 3 · 2016-03-12T07:12:00

C++

#include<stdio.h>
main()
{
    int x,y,w; //ad another integar
    float z;
    printf("Write 2 integers: ");
    scanf("%d%d",&x,&y);
    if((x+y==8 || x+y==10)) w=1;//state condition 0
    if(x+y>0 && x+y<=4) w=0;//state condition 1

    switch (w) // replace here by w
    {
    case 0:      // replace here by w      
        z = exp(x+y);
        printf("%f is an output.\n",z);
        break;


    case 1 :   // replace here by w
    z = (pow(x,2)+y)/(x-y);
    printf("%f is an output.\n",z);
    break;

    default:
        z = 0;
        printf("%f is an output.\n",z);
    }
    return 0;
}

Could you help me solve this problem?

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