How to write insert query into windows form application using C#

Question

1.00/5 (1 vote)

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C#

private void button2_Click(object sender, EventArgs e)
       {
           string con = @"Data Source=.\SQLEXPRESS;AttachDbFilename=C:\Users\Ravi\Documents\OnlineBanking.mdf;Integrated Security=True;Connect Timeout=30;User Instance=True";
           SqlConnection conn = new SqlConnection(con);
           conn.Open();
           SqlCommand chk = new SqlCommand("Insert into Registration(Name)values(@Name)",conn);

           chk.Parameters.AddWithValue("@Name", textBox1.Text);
           chk.ExecuteNonQuery();

           MessageBox.Show("Account created successfully!!!");
       }

What I have tried:

I am unable to insert value into database.. plz rectify my error.

Posted 2-Apr-16 6:48am

HellHotie

Updated 2-Apr-16 7:45am

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Karthik_Mahalingam 2-Apr-16 12:59pm

what is the error message ?

1 solution

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Arvind Zamakia · Answer 1 · 2016-04-02T07:45:00

Solution 1

Hello, Try this code

C#

private void button2_Click(object sender, EventArgs e)
       {
           string con = @"Data Source=.\SQLEXPRESS;AttachDbFilename=C:\Users\Ravi\Documents\OnlineBanking.mdf;Integrated Security=True;Connect Timeout=30;User Instance=True";
           SqlConnection conn = new SqlConnection(con);
           SqlCommand chk = new SqlCommand("Insert into Registration(Name)values(@Name)",conn);
	chk .CommandType = CommandType.Text;
    chk .CommandText = sqlQuery;
    chk .Parameters.Add("@Name", textBox1.Text);
     chk .Open();
    chk .ExecuteNonQuery();
    chk .Close();
 
           MessageBox.Show("Account created successfully!!!");
       }

Posted 2-Apr-16 7:45am

Arvind Zamakia

Updated 2-Apr-16 8:36am

v3

Comments

Karthik_Mahalingam 2-Apr-16 13:51pm

what is that sqlQuery in the below line
chk .CommandText = sqlQuery;

the commandText is already defined in
SqlCommand chk = new SqlCommand("Insert into Registration(Name)values(@Name)",conn);

Tips: whenever posting a solution, try to add the codes in the Code block.
Thanks
KARTHIK

Arvind Zamakia 2-Apr-16 14:04pm

comment this line and try now

Karthik_Mahalingam 2-Apr-16 14:57pm

ha ha,why should i try.. let the OP try.

HellHotie 2-Apr-16 22:28pm

Sorry it was my mistake have been resolved.. ty