How to get lowest location of controls in array using linq

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how to get lowest location of controls in array using linq

i have array of controls say
dim oClipboard() as control

i needed the control which has lowest location or minimum location value from tha oclipboard

What I have tried:

so far i have tried linq with min function

Dim p = c.Select(Function(g) g.Location).Min.ToString
Dim x = c.Select(Function(g) g).Min(Function(h) h.Location)

both of above give me error stated below

System.ArgumentException was unhandled
HResult=-2147024809
Message=At least one object must implement IComparable.
Source=mscorlib
StackTrace:
at System.Collections.Comparer.Compare(Object a, Object b)
at System.Collections.Generic.ObjectComparer`1.Compare(T x, T y)
at System.Linq.Enumerable.Min[TSource](IEnumerable`1 source)
at System.Linq.Enumerable.Min[TSource,TResult](IEnumerable`1 source, Func`2 selector)

is there any way i could get control whhich has lowest location

Posted 6-May-16 0:10am

Omkaara

Updated 15-May-16 7:16am

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Comments

BillWoodruff 7-May-16 0:24am

Note that if your collection of Controls includes Controls that are nested in other Controls, or Controls from more than one Form, then you will need to translate the Location value for each Control into screen co-ordinates before comparing.

2 solutions

Solution 2

What's wrong with Enumerable.Min()[^] and Enumerable.Max()[^] functions?

C#

var lowest = c.Min(x=>x.Location.Y);
var highest = c.Max(x=>x.Location.Y);

Posted 15-May-16 7:16am

Maciej Los

Updated 15-May-16 7:25am

v2

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OriginalGriff · Accepted Answer · 2016-05-06T00:26:00

Solution 1

Try something like:

C#

Control lowest = myControls.OrderByDescending(c => c.Location.Y).First();

VB (untested):

C#

Dim lowest As Control = myControls.OrderByDescending(Function(c) c.Location.Y).First()

Posted 6-May-16 0:26am

OriginalGriff

Comments

Omkaara 6-May-16 6:33am

@OriginalGriff how many times i have to tell you that you are genius!!!!

OriginalGriff 6-May-16 6:42am

One is probably too many... :blush: