If old password and new password consecutive characters are greater than 3 then it should show some error. I want to implement same in javascript

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1.00/5 (1 vote)

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Below code is in java :

private static final int PASSWORD_MAX_CONS_LENGTH = 3;
for (int i = 0; i < oldPassword.length() - PASSWORD_MAX_CONS_LENGTH + 1; i++) {
if (passwordString.indexOf(oldPassword.substring(i, i
+ PASSWORD_MAX_CONS_LENGTH)) >= 0)

Now we want the same validation in java script ?

How can I compare the same in java script.

Here, we are checking if old password and new password consecutive character is greater than 3 then should throw error.

Same thing I want in java script:

If old password and new password consecutive characters are greater than 3 then it should show some error.

What I have tried:

var PASSWORD_MAX_CONS_LENGTH = 3;
if (oldPassword != null) {
if (oldPassword.length() - PASSWORD_MAX_CONS_LENGTH ) {
if (userpassword.indexOf(oldPassword)...

Posted 6-Jun-16 19:52pm

Member 12539934

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Member 12539934 7-Jun-16 2:41am

I tried this but it is not working :

function checkPasswordValue(username, userpassword,oldPassword) { var old_password = document.getElementsByName("OldPassword"); var old_password_value= old_password[0].value; if (old_password_value != null) { if (userpassword.indexOf(old_password_value.match((/^\/{3}/)) >= 0) { return false; } return true; } }

Sergey Alexandrovich Kryukov 7-Jun-16 3:09am

Why any password manipulations on client side? It it for a Web site or what?
—SA

Member 12539934 7-Jun-16 3:31am

All validations we are changing from java to java script(client side)

Sergey Alexandrovich Kryukov 7-Jun-16 3:34am

There is no such thing as "Java script".
You should never even store passwords anywhere, forget about client-side validation, which can be easily worked around; not just easily, but in no time. So easy that it makes password protection pointless.
Storing passwords is never needed for authentication. Normally, cryptographic hash functions are used.
—SA

Mohibur Rashid 7-Jun-16 4:51am

So, if some user modify the javascript code and validate anything... what would happen?

Member 12539934 9-Jun-16 6:55am

PASSWORD_MAX_CONS_LENGTH = 3;
if (oldPassword != null) {
for (int i = 0; i < oldPassword.length() - PASSWORD_MAX_CONS_LENGTH +1; i++) {
if (passwordString.indexOf(oldPassword.substring(i, i
+ PASSWORD_MAX_CONS_LENGTH)) >= 0) {
errors.add(ERROR_PASS_CONS_PREV_PASS);
break;
}
}
}

It is giving me error even if 3 consecutive letters are same. It should throw error only if it is greater than 3.
This logic is little complicated :
if (passwordString.indexOf(oldPassword.substring(i, i
+ PASSWORD_MAX_CONS_LENGTH)) >= 0)
Can we use any regular expressions which can check that if more than 3 characters are same with the old password, it should throw error.
If it is 3, it should not give any error.

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