ORDER by items must appear in the select list if SELECT DISTINCT is specified.

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SQL-Server-2008R2

SQL

SELECT DISTINCT MG.IDNO   ,MG.LOANUMBER,MG.PERIOD  ,MG.YEAR1 ,
          MG.TX_DATE,MG.TY_DATE  ,MG.ACCRUED ,MG.SACCRUED,
          MG.OPENING,MG.PAYMENT  ,MG.INTEREST,MG.REPAY,MG.CLOSING,
          L.CUSTOMER,(MG.IDNO+''+MG.LOANUMBER) AS IDNOLOAN
  FROM MGBALANCE MG
  LEFT  JOIN LOANS L
  ON MG.IDNO=L.IDNO
  WHERE MG.IDNO= @ZIDNO AND
  CONVERT(NVARCHAR, MG.YEAR1) + Right('00' +  Convert(varchar(10), MG.PERIOD), 2)  BETWEEN @STAT AND @END
  ORDER BY   MG.IDNO,MG.LOANUMBER,CONVERT(NVARCHAR,MG.YEAR1) + Right('00' +  Convert(varchar(10),MG.PERIOD), 2),TX_DATE

Have the above error message when I introduced the 'DISITNCT' syntax.

Please rectify the problem above.

Thanks

What I have tried:

Checked my earlier codes and the interner

Posted 17-Jul-16 4:43am

Member 10744248

Updated 17-Jul-16 5:27am

v3

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OriginalGriff · Answer 1 · 2016-07-17T05:27:00

The error is fairly clear, if you think about it: You cannot use SELECT DISTINCT unless all of the items in the ORDER BY clause are included in the SELECT.
Why not? Well if you don't, which items are distinct? There may be multiple rows in the ORDER BY which are different, but which aren't DISTINCT unless all the ordering columns are present - so which should SQL choose to discard? It doesn't want to make that decision - because it really hates giving you the wrong info - so instead it passes the buck back to you to change your query so that distinct means distinct! :laugh: