Instance of class

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Hi, I wanted to know if exists up a way to instantiate a class using a variable "myClass" and invoke a method and present a variable inside a variable always through. Example:

myClassName string;
metodName string;
string variableName;
For the class:
Assembly a = Assembly.Load ("MyLibrary");
Type t = a.GetType (MyLibrary.MyClass ");
object obj = Activator.CreateInstance (t);
For the method and variable?
t.xxxxxx (metodName)
t.xxxxxx (variableName)

thanks

Posted 29-Sep-10 6:52am

Gennaro Voto

Updated 29-Sep-10 7:30am

Abhinav S

v2

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#realJSOP · Answer 1 · 2010-09-29T07:06:00

Solution 1

Googling "c# instantiate class by name" would have led you here (as well as over 95,000 other results):

http://www.csharphelp.com/archives/archive200.html[^]

Posted 29-Sep-10 7:06am

#realJSOP

*dan!sh* · Answer 2 · 2010-09-29T08:35:00

Solution 2

An object of class Type has a method InvokeMember. That is what you are looking for. Check out MSDN on how to use it.

Posted 29-Sep-10 8:35am

dan!sh

Chris Trelawny-Ross · Answer 3 · 2010-09-29T09:44:00

How about using the Dynamic Language Runtime introduced in .Net 4.0?

That way you don't have to invoke anything to access members of an object whose type is unknown to the compiler.

Or ...

Have MyClass implement IMyPluginInterface - where the interface declares the members that should be exposed - then:

IMyPluginInterface someObject = (IMyPlugInInterface)Activator.CreateInstance("MyLibrary", "MyClass");
someObject.SomeMethod();
...

N_tro_P · Answer 4 · 2010-09-29T11:09:00

Solution 4

What you are asking about is called "Reflection". The Activator as Chris posted will do exactly what you need and it is done by Reflection if you want to know more about the topic.

Posted 29-Sep-10 11:09am

N_tro_P

Abhishek Sur · Answer 5 · 2010-09-29T12:51:00

Solution 5

The easiest way to do this is to use Dynamic.

Internally .NET uses Reflection to invoke your member,just you dont need to do these calls

Posted 29-Sep-10 12:51pm

Abhishek Sur