How to send email attachment in C# without reloading the page.

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I have done already a simple email sending with attachment in C# and it works but it needs to reload the page. How can I do an email sending with attachment without reloading the page?

I have tried using jquery calling a controller from the view:

[$.post(url, {attachment : attachment }, function(data){}); ]

but i'm having problems with the URL and the restriction of browsers when I'm getting the file destination on the controller part.

is there another way to do this? without reloading the whole page for the attachment.

thanks!

What I have tried:

$.post(url, {attachment : attachment }, function(data){});

this returns null on the parameter of the controller.

Posted 18-Nov-16 4:30am

jhayMe

Updated 22-Nov-16 18:04pm

v2

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Comments

F-ES Sitecore 18-Nov-16 10:38am

Google "ajax file upload" and you'll find lots of examples of how to do this.

jhayMe 18-Nov-16 18:23pm

should i upload it first?

ZurdoDev 18-Nov-16 11:01am

To send email you must run server side code so to do that without posting back you use jquery's ajax() method.

Er. Puneet Goel 22-Nov-16 3:24am

Hey! Have you got the solution or still need some help ?

jhayMe 22-Nov-16 16:39pm

still in need. Getting the file to controller is not a problem anymore but sending details from the view to controller with it ( such as email TO , email From, body of email, etc) is what I have problem with.

Er. Puneet Goel 24-Nov-16 5:06am

Please share your code, what have you done so far?

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Saumendra Pattanaik · Answer 1 · 2016-11-22T18:04:00

C#

if (attachmentFilename != null)
{
    Attachment attachment = new Attachment(attachmentFilename, MediaTypeNames.Application.Octet);
    ContentDisposition disposition = attachment.ContentDisposition;
    disposition.CreationDate = File.GetCreationTime(attachmentFilename);
    disposition.ModificationDate = File.GetLastWriteTime(attachmentFilename);
    disposition.ReadDate = File.GetLastAccessTime(attachmentFilename);
    disposition.FileName = Path.GetFileName(attachmentFilename);
    disposition.Size = new FileInfo(attachmentFilename).Length;
    disposition.DispositionType = DispositionTypeNames.Attachment;
    message.Attachments.Add(attachment);                
}