How do I create a C program

Question

1.00/5 (1 vote)

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Create a program that will ask the user for his/her final grade and it display the equivalent grade (refer to below table) and its remarks.
Grade
Equivalent
Remarks
from
to
no.
letter

0.0
59.4
0.00
F
???
59.5
64.4
1.00
D
???
64.5
70.4
1.50
D+
???
70.5
76.4
2.00
C
???
76.5
82.4
2.50
C+
???
82.5
88.4
3.00
B
???
88.5
94.4
3.50
B+
???
94.5
100.0
4
A
???

What I have tried:

#include<stdio.h>
main() {

/* This program will ask the user for their final grade and it will display the equivalent grade(refer to the below table) & its remarks
note:- you are the one to create your own remarks. the remarks should inspire them
Grades
from 0.0 to 59.4 is number (0.0) which F in letter
from 59.5 to 64.4 is number (1.00) which is D
from 64.5 to 70.4 is number (1.50) which is D+
from 70.5 to 76.4 is number (2.00) which is C
from 76.5 to 82.4 is number (2.50) which is C+
from 82.5 to 88.4 is number (3.00) which is B
from 88.5 to 94.4 is number (3.50) which is B+
from 94.5 to 100.0 is number (4) which is A
sample output
enter your fina grade : 55
equivalent grade is 0.0 or F
remark= "Have a nice vacation"
*/
int grade,equi_grade_num,remarks;
grade=0 to 100.0
char a, b, c, d, f, p, l, u;
a='A';
b='B';
c='C';
d='D';
f='F';
p='B+';
l='C+';
u='D+';

printf("Input your final grade: ");
scanf("%d",&grade);

printf("Your equivalent grade is %d: or %c: ");
scanf("%d" "%c",&equi_grade_num,&a,&b,&c,&d,&f,&p,&l,&u);

if (grade==0 || grade<=59.4) {
scanf("%d" "%c",&equi_grade_num,&a,&b,&c,&d,&f,&p,&l,&u);
printf("Failed,needs immediate improve");
}

getch();
}

Posted 11-Mar-17 23:09pm

Member 13053749

Updated 11-Mar-17 23:42pm

OriginalGriff

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OriginalGriff · Accepted Answer · 2017-03-11T23:42:00

Solution 1

That isn't going to work - as you have probably noticed!
A char variable can only hold a single "letter", so things like this:

p='B+';
l='C+';
u='D+';

Will not compile.
Go back a stage, and think again: do this in stages.
Start by getting a grade from the user, and storing it in an appropriate variable - and int variables only hold integer values, so they don't work with "59.4", or "88.5". You will have to use a different data type for your grade.

When you have that working (and by that I mean compile it, run it and make sure that when the user enters a value you can read it as a number and print it back out correctly, rejecting any "bad" inputs like "hello") look at working out which "group" the grade falls into. That's not complex, it's just a set of if...else if...else if...else statements:

C++

if (grade >= lowestGradeInFirstGroup && grade <= highestGradeInFirstGroup)
   {
   ... In first group
   }
else if (grade >= lowestGradeInSecondGroup && grade <= highestGradeInSecondGroup)
   {
   ... in second group
   }
...
else
   {
   ... in last group
   }

When you have that working (compiling and running ok) look at printing the appropriate grade code and message.

Do it in stages, and it'll be pretty easy!
But ... this is your homework, so the code is all up to you!

Posted 11-Mar-17 23:42pm

OriginalGriff

Comments

Member 13053749 12-Mar-17 6:25am

but how do i display an equivalent grade to the grade input

OriginalGriff 12-Mar-17 6:37am

printf?

Member 13053749 12-Mar-17 7:01am

like how about this :- float grade, equivalent_grade_num;
char letter;
int p,l,u;
p=(B+);
l=C+;
u=D+;
letter={'A','B','C','D','F'};

printf("Enter your final grade: ");
scanf("%f",&grade);

equivalent_grade_num=0.0
if (grade==0.0 || grade<=59.4)
printf("Your equivalent grade is %f or %c%d",eqivalent_grade_num,letter,p,l,u);

OriginalGriff 12-Mar-17 7:10am

Better, but... it won't compile!
Why do you need "equivalent_grade_num" at all? Why have p, l, u? Why "letter"?

Have you considered using a fixed string in each if block?

Member 13053749 12-Mar-17 9:22am

how about this

float G;

printf("\nEnter your final grade: ");
scanf("%f",&G);

if (G>=0.0 && G<=59.4){
printf("\nYour equivalent grade is 0.0/F!!");
printf("\n\nYou failed!!, this is really very poor performance");
}
else if(G>=59.5 && G<=64.4){
printf("\nYour equivalent grade is 1.00/D!!");
printf("\n\nYou were just decimal points away to fail, you must apply extensive persistence!!!!!");
}
else if (G>=64.5 && G<=70.4){
printf("\nYour equivalent grade is 1.50/D+!!");
printf("\n\nYou ");
}
else if(G>=70.5 && G<=76.4){
printf("\nYour equivalent grade is 2.00/C!!");
printf("\n\nYou");
}
else if(G>=76.5 && G<=82.4){
printf("\nYour equivalent grade is 2.50/C+!!");
printf("\n\nYou ");
}
else if(G>=82.5 && G<=88.4){
printf("\nYour equivalent grade is 3.00/B!!");
printf("\n\nYou ");
}
else if(G>=88.5 && G<=94.4){
printf("\nYour equivalent grade is 3.50/B+!!");
printf("\n\nYou ");
}
else if(G>=94.5 && G<=100.0) {
printf("\nYour equivalent grade is 4/A!!");
printf("\n\nYou passed succesfully, congratz to your exceptional achievement!!");
}

OriginalGriff 12-Mar-17 9:33am

Call it "grade" instead of "G" (it's a good idea to get used to "proper" names for variables, it makes code a lot more readable especially when it gets bigger than this) but other than that and a few spelling / grammar errors in the messages that should work fine!
Have you tested it?

Member 13053749 12-Mar-17 10:01am

ya i will correct the grammar errors .. but just one last question .. i hhave tested it , it works but when i input the exact numbers like 64.4 or 70.4 it doesnt display the message i dnt know why

OriginalGriff 12-Mar-17 10:53am

What does it do?
Have a look at what is going on with the debugger - I can't give you instructions as I have no idea what system you are using to write and compile it, but if you google "debugger" and the name of the application you are using you should find all the instructions you need.

Put a breakpoint on the first line in the function, and run your code through the debugger. Then look at your code, and at your data and work out what should happen manually. Then single step each line checking that what you expected to happen is exactly what did. When it isn't, that's when you have a problem, and you can back-track (or run it again and look more closely) to find out why.

Member 13053749 12-Mar-17 11:11am

thank u so much :)

OriginalGriff 12-Mar-17 11:19am

You're welcome!