How to run an executable file but keep the console of executable file hidden in C# code?

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I have an executable file which I need to run in a C# code but the console should be hidden while it is running.

Below is the code I used to run the executable file:
----------------------------------------------------
Process process = new Process();
process.StartInfo.FileName = ".\\ABC.exe";
process.Start();
----------------------------------------------------

Request you to please suggest how this can be achieved.

What I have tried:

Process process = new Process();
process.StartInfo.FileName = ".\\ABC.exe";
process.Start();

Posted 13-Sep-17 3:00am

Member 10536462

Updated 13-Sep-17 4:00am

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OriginalGriff · Answer 1 · 2017-09-13T03:14:00

Solution 1

See here: ProcessStartInfo.CreateNoWindow Property (System.Diagnostics)[^] and read the "Remarks" section.

Posted 13-Sep-17 3:14am

OriginalGriff

Member 10536462 · Answer 2 · 2017-09-13T04:00:00

Solution 2

i just figured it out and would like to share the same piece of code with all:

Process process = new Process();
process.StartInfo.FileName = ".\\ABC.exe";
process.StartInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
process.Start();

Posted 13-Sep-17 4:00am

Member 10536462

Updated 13-Sep-17 4:01am

Comments

Dave Kreskowiak 13-Sep-17 10:37am

No thanks. I'll just read the documentation on the ProcessStartInfo class, 'cause that's where they hide this kind of basic information.