Create the following 10 x 5 grid with ‘*’ and ‘O’ characters. Each row must have exactly one ‘O’ character, and the position of ‘O’ characters must be random.

Question

1.00/5 (1 vote)

See more:

*******O**
******O***
******O***
*O********
*****O****

What I have tried:

i=1
m=0
while i<=5:
    j=1
    m=m+1

    while j<=10:
        if j==m+7:
            print('O',end='')
        else:
            print('*',end='')
        j=j+1
    print()
    i=i+1

Posted 2-Oct-17 4:42am

Member 13441210

Updated 2-Oct-17 6:10am

Dave Kreskowiak

v2

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Dave Kreskowiak · Answer 1 · 2017-10-02T05:51:00

Solution 1

OK, so you have to basic logic down. You just need to replace the "m=m+1" line with something that generates a random number, "m=something...".

You should also get rid of the "m+7" thing and make that just "m".

Posted 2-Oct-17 5:51am

Dave Kreskowiak

Richard MacCutchan · Answer 2 · 2017-10-02T06:10:00

Solution 2

See 9.6. random — Generate pseudo-random numbers — Python 3.4.7 documentation[^].

Posted 2-Oct-17 6:10am

Richard MacCutchan