C++ input and output

Question

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so i wanna make my program go like if i enter few numbers, in range of 0-50 51-100 it shows how many numbers are 0-50 in astricks and same for 5-100

eg i enter 23, 34,89,99,67,1,2.

i want it to be like 0-50 ****
51-100 ***

but my currently i get the asterick after i enter the number, so i i say 0-50 display *, 51-100 display !, after each number it shows the symbol instead of taking all the numbers and display the symbol the the end.

my first time actually coding so i know i am dumb.

What I have tried:

#include <iostream>

using namespace std;

int main()
{
int PSI;

for (int i =0; i<7; i++)
{
cin >> PSI;

if (PSI>=0 , PSI<=50){

cout << "*" << endl;
}
else if (PSI>=51,PSI<=100)
cout << "*" << endl;

}

return 0;
}

Posted 9-Oct-17 2:56am

Member 13452896

Updated 9-Oct-17 3:28am

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Comments

Richard Deeming 10-Oct-17 12:47pm

REPOST
You have already posted this homework question:
https://www.codeproject.com/Questions/1209696/Bar-chart-Cplusplus-need-help-asap[^]

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CPallini · Accepted Answer · 2017-10-09T03:28:00

You should maintain counters for range hits, e.g.

C++

#include <iostream>
using namespace std;

int main()
{
  int pres;

  int inrange[2]={0};
  string range[2]  = {"  0- 50 ", " 51-100 "};

  for (int i =0; i<7; i++)
  {
    cin >> pres;
    if ( (pres>= 0) && (pres <= 50) )
      ++inrange[0];
    else if ( (pres > 50) && (pres <=100))
      ++inrange[1];
    else
    {// handle 'out of range' pressure

    }
  }

  for (int i=0;i<2; ++i)
  {
    cout << range[i];
    for (int j=0; j<inrange[i]; ++j)
      cout << "*";
    cout << endl;
  }
}