Why my ordered string something wrong

See more:

C

#include <stdio.h>
#include <stdlib.h>
int compare(char info[][20], int n);
void read();
void swap(char *ap, char *bp);
int main()
{
read();

return 0;
}
void read()
{
int n,c;
printf("Enter how many names you want to sort.\n");
scanf("%d", &n);
printf("Please enter %d names.\n", n);
char *info[n][20];

for(c=0;c<n;c++) //store input in array
{
scanf("%s", info[c]);
}

printf("Entered strings:\n");
for(c=0;c<n-1;c++)
{
printf("%s\n",info[c]);
}
compare(info,n);
printf("ordered strings:\n");
for(c=0;c<n;c++)
{
printf("%s\n",info[c]);
}
}
int compare(char info[][20], int n)
{
int c = 0;
char *ap;
ap = info[c];

char *bp;
bp = info[c+1];
int y = 0;
printf("%s, %s", ap, bp);
for(y = 0; y < n; y++)
{

while(*ap == *bp)
{
if (*ap == '\0' && *bp == '\0')
{
return 0;
break;
}
ap++;
bp++;
}
if (*ap < *bp)
{
return 1;
}
if (*ap > *bp)
{
swap(ap, bp);
return -1;
}
}
if (*ap < *bp)
{
return 1;
}
if (*ap > *bp)
{
swap(ap, bp);
return -1;
}
}


void swap(char *ap, char *bp)
{

char tmp;
int x = 0;
while(*ap != '\0' || *bp != '\0')
{

tmp = *ap;
*ap = *bp;
*bp = tmp;
ap++;
bp++;
}
}

What I have tried:

try to print something in code but still don't know how to fix it.