How to print 3 or more alphabets in a string

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if n=4, then the output should be MNOM

I am not getting the logic of how to print O here because there are 3 alphabets here. In 2 alphabets I can use even and odd logic but what should I do here.Please help me

What I have tried:

class Main {
  public static void main(String[] args) {
    int n=8;
    String str="";
    
    for(int i=1;i<=n;i++)
    {
      if(i%2!=0)
      {
        str=str+"M";
      }
      else
      {
        str=str+"N";
      }
      System.out.println(str);
      
    }
  }
}

Posted 13-Mar-18 11:21am

Member 13724614

Updated 13-Mar-18 12:31pm

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Member 13724614 13-Mar-18 17:50pm

solved it. yesssss!!!!

2 solutions

Solution 2

You code can be easily generalized. Try, for instance

Java

class Main
{
  public static String build(int letters, int length)
  {
    StringBuilder sb = new StringBuilder();
    for (int n=0; n<length; ++n)
    {
      sb.append((char)('M'+ n % letters));
    }
    return sb.toString();
  }

  public static void main( String args[])
  {
    String msg1 = build(2, 4);
    String msg2 = build(3, 4);
    System.out.printf("msg1 '%s', msg2 '%s'\n", msg1, msg2);
  }
}

Posted 13-Mar-18 12:32pm

CPallini

Comments

Member 13724614 13-Mar-18 20:55pm

Sir, I am a beginner and very new to java. I appreciate your efforts but this code that you have written, I could not get it. Please make me understand this, I will be really grateful to you.

CPallini 14-Mar-18 5:23am

You are using (i % 2) result, that is either 0 or 1 to distinguish between 'M' and 'N'. Since 'N' character code is equal to 'M' character code plus one, then
'M' + (i % 2)
replaces your conditional statements.
That could be easily generalized to
'M' + (i % 3)
'M' + (i % 4)
...

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Member 13724614 · Accepted Answer · 2018-03-13T11:51:00

class Main {
  public static void main(String[] args) {
    int n=8;
    String str="";
    
    for(int i=1;i<=n;i++)
    {
      if(i%3==1)
      {
        str=str+"M";
      }
      if(i%3==2)
      {
        str=str+"N";
      }
      if(i%3==0)
      {
        str=str+"O";
      }
    }
      System.out.println(str);
    
  }
}