Print unexpected output i.e undefinedranjan

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JavaScript

var str="ranjan";
var i;
for(i=0;i<str.length;i++)
{
	var text;
	text =""+text+str[i];
}
console.log(text);

What I have tried:

output will be undefinedranjan

Posted 6-May-18 1:22am

RANAJN SONU

Updated 6-May-18 4:23am

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Thomas Daniels · Answer 1 · 2018-05-06T01:49:00

Try this:

JavaScript

var str="ranjan";
var i;
var text = "";
for(i=0;i<str.length;i++)
{
	text += str[i]; // equal to text = text + str[i];
}
console.log(text);

Your original code doesn't work because at the first time text = "" + text + str[i] runs, text would be undefined.

Also worth noting that in the above code block, var text = ""; must be outside the for loop, otherwise you'd redefine text as empty string each iteration.

Patrice T · Answer 2 · 2018-05-06T04:25:00

Solution 1 already gave you an explanation, this solution tells you how to see what is going on by yourself.
-----
Your code do not behave the way you expect, and you don't understand why !

There is an almost universal solution: Run your code on debugger step by step, inspect variables.
The debugger is here to show you what your code is doing and your task is to compare with what it should do.
There is no magic in the debugger, it don't know what your is supposed to do, it don't find bugs, it just help you to by showing you what is going on. When the code don't do what is expected, you are close to a bug.
To see what your code is doing: Just set a breakpoint and see your code performing, the debugger allow you to execute lines 1 by 1 and to inspect variables as it execute.
Debugger - Wikipedia, the free encyclopedia[^]
JavaScript Debugging[^]
Chrome DevTools | Web | Google Developers[^]
The debugger is here to only show you what your code is doing and your task is to compare with what it should do.