How do I return int in my code ?

Question

1.44/5 (2 votes)

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I have unwanted number "200" at the end in console.

What I have tried:

Java

public class Main {

    public static void main(String[] args) {
        Main m = new Main();

        
        System.out.println(m.multiplicationTable(10, 20));

    }

    
    public int multiplicationTable(int number1, int number2) {
        int result = 0;
        for (int j = 11; j <= number2; j++) {
            for (int i = 1; i <= number1; i++) {

                System.out.println(i + " * " + j + " = " + i * j);
                result = i * j;

            }
        }

        return result;
    }
}

Posted 8-May-18 9:09am

Member 13817762

Updated 8-May-18 9:51am

Thomas Daniels

v2

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2 solutions

Solution 2

Quote:
I have unwanted number "200" at the end in console.

You forgot to tell us what is wanted, so we can only guess.
By design you code print the last result of multiplication table after the table.
This code is simple enough to be a good candidate for debugger learning.
There are 2 reasons to learn debugger:
- You learn ways to find bugs by yourself.
- you improve your understanding of code and thus your learning curve.
-----
Your code do not behave the way you expect, and you don't understand why !

There is an almost universal solution: Run your code on debugger step by step, inspect variables.
The debugger is here to show you what your code is doing and your task is to compare with what it should do.
There is no magic in the debugger, it don't know what your is supposed to do, it don't find bugs, it just help you to by showing you what is going on. When the code don't do what is expected, you are close to a bug.
To see what your code is doing: Just set a breakpoint and see your code performing, the debugger allow you to execute lines 1 by 1 and to inspect variables as it execute.
Debugger - Wikipedia, the free encyclopedia[^]
http://docs.oracle.com/javase/7/docs/technotes/tools/windows/jdb.html[^]
https://www.jetbrains.com/idea/help/debugging-your-first-java-application.html[^]
The debugger is here to only show you what your code is doing and your task is to compare with what it should do.

Posted 8-May-18 9:53am

Patrice T

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Thomas Daniels · Accepted Answer · 2018-05-08T09:17:00

These two lines contribute to causing the unwanted "200":

Java

System.out.println(m.multiplicationTable(10, 20));

Java

return result;

The whole printing of the multiplication table happens because of the printlns inside multiplicationTable. The last one is 10 * 20, or 200, and you store that in result, which you then return. And you wrote the instruction to print this return value.

To avoid that "200" at the end, make multiplicationTable a void, drop the result variable (if you don't want to return anything, the whole variable becomes useless), drop the return statement and replace System.out.println(m.multiplicationTable(10, 20)); with m.multiplicationTable(10, 20);.

How do I return int in my code ?

2 solutions

Solution 1

Solution 2

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