How to display string[] result in label

Question

0.00/5 (No votes)

See more:

hi,

i have a filename file001.mmgr of string[,] type how can i display the filename in label in form load

What I have tried:

int count = 0;
          if (resp!= "")
          {
              XmlDocument readDoc = new XmlDocument();
              readDoc.LoadXml(resp);
              count = readDoc.SelectNodes("college/sno").Count;
              filename = new string[count, 1];
              // alternately, _doc.Load( _strFilename); to read from a file.
              XmlNodeList xfile_name = readDoc.GetElementsByTagName("file_name");

              for (i = 0; i < count; i++)
              {
                  filename[i, 0] = xfile_name[i].InnerText;

              }
              //lbldssFilename.Text = filename[i].ToString();
              string[,] dfilename = filename;
              lbldssFilename.Text = dfilename.ToString();
          }
          else
          {
              string[,] a = new string[1, 0];
          }
      }

Posted 12-Jul-18 17:41pm

Member 13846964

Updated 12-Jul-18 18:10pm

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Bryian Tan · Answer 1 · 2018-07-12T18:10:00

Based on what you have posted, dfilename/filename is a MultiDimensional Array / Object and .ToString() will print out the name of the Object. The easiest way is to use Linq to select all the file names and then use the string.join method to display all the items in comma separator.

C#

using System;
using System.Linq;

public class Program
{
	public static void Main()
	{
		var filenames = new string[2, 2];
		filenames[0, 0] = "abcd00";
		filenames[0, 1] = "abcd01";
		filenames[1, 0] = "abcd10";
		filenames[1, 1] = "abcd11";
		
		string[,] dfilename = filenames;
		
		var fName = from string filename in dfilename
                     select filename;
		
		Console.WriteLine("dfilename: " + string.Join(",", fName));  
	}
}

Output:
dfilename: abcd00,abcd01,abcd10,abcd11