What is the intended block here?

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1.00/5 (1 vote)

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I'm a beginner to python. So want to know the problem here.

What I have tried:

Python

print('type a number:')
number=int(input("Enter a number"))
if (number % 2)!=0 :
return "Weird"
elif :
(2<=n=>5)
print("Not Weird")

elif :
(6<=n=>20)
print("Weird")

elif:
(n>20)
print("Not Weird")

Posted 26-Jul-18 0:15am

Member 13926529

Updated 26-Jul-18 1:37am

Patrice T

v2

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Jochen Arndt · Answer 1 · 2018-07-26T00:34:00

That can't be actually answered because your posted code has no indentation at all while Python requires proper indentation.

But your elif statements are wrong. Their syntax is similar to those of if statements (see 4. More Control Flow Tools — Python 2.7.15 documentation[^] ):

Python

if [expression]:
    # code to be executed when condition is true goes here
elif [expression]:
    # code to be executed when condition is true goes here
# End of if - elif here

CPallini · Answer 2 · 2018-07-26T01:35:00

Solution 2

It should be:

Python

print('type a number:')
n = int(input("Enter a number: "))
if (n % 2) !=0 :
  print("Weird")
elif (n>= 2 and n<=5):
  print("Not Weird")
elif (n>= 6 and n<=20):
  print("Weird")
elif (n>20):
  print("Not Weird")

Posted 26-Jul-18 1:35am

CPallini

Richard MacCutchan · Answer 3 · 2018-07-26T01:38:00

Solution 3

See The Python Tutorial — Python 3.4.9rc1 documentation[^].

Posted 26-Jul-18 1:38am

Richard MacCutchan

What is the intended block here?

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