I want to run "setval" function completed after then that "afterfirstfunc" function will go to execute

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i want to run "setVal" function Completed after then that "afterFirstFunc" function will go to execute,

var setVal = function() {
var dfd=$.Deferred();
for (var i = 0; i < 5; i++) {
(function (i) {
setTimeout(function () {
console.log("Inside First "+i);
}, 1000*i);
})(i);
};
dfd.resolve();
return dfd.promise();
};
var setVal1=function(){
var dfd1=$.Deferred();
for (var i = 0; i < 5; i++) {
(function (i) {
setTimeout(function () {
console.log("Inside Second "+i);
}, 1000*i);
})(i);
};
dfd1.resolve();
return dfd1.promise();
};
setVal().then(function(){
setVal1(); 
});

What I have tried:

i want to execute setVal1 run first then setVal1 will go to execute, not both the function work parallel, i have tried all the thing but nothing help me to achieve this

Posted 3-Sep-18 22:46pm

Member 13972185

Updated 5-Sep-18 8:08am

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Richard Deeming · Answer 1 · 2018-09-05T08:09:00

You resolve the promise returned from setVal before any of the setTimeout calls have executed.

You need to wait until all of the setTimeout calls have completed before resolving the promise. You'll want to create a separate promise for each call, and use Promise.all[^] to wait for them all to complete.

JavaScript

var delay = function(time, value){
    return new Promise(function(resolve) {
        setTimeout(resolve.bind(null, value), time);
    });
};

Promise.prototype.delay = function(time) {
    return this.then(function(value) {
        return delay(time, value);
    });
};

var setVal = function(){
    var promises = [];
    for (var i = 0; i < 5; i++){
        promises.push(Promise.resolve(i).delay(i * 1000).then(function(i){
            console.log("Inside first", i);
        }));
    }
    
    return Promise.all(promises);
};

var setVal1 = function(){
    var promises = [];
    for (var i = 0; i < 5; i++){
        promises.push(Promise.resolve(i).delay(i * 1000).then(function(i){
            console.log("Inside second", i);
        }));
    }
    
    return Promise.all(promises);
};

setVal().then(setVal1);

javascript - using setTimeout on promise chain - Stack Overflow[^]
Promise - JavaScript | MDN[^]