If instr(mymessage, "I'") <> 0 then = compiler bug ?

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I have written a visual basic macro in Excel
I am looking for the strings I'm I'll I'd
Coding as above using "I'" bypasses the text

What I have tried:

Searching for I'm separately does not work either
Using ""I'm"" gives a compilation error
Any workarounds greatly received for 67 year old coder with 50 years IT experience.
Darrell

Posted 26-Feb-19 11:59am

Member 14163890

Updated 26-Feb-19 20:31pm

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Patrice T 26-Feb-19 18:03pm

A coder with 50 years of experience should know that showing its code is the first thing to do wheb requesting help.

Member 14163890 26-Feb-19 18:09pm

YJanks for your prompt reply. The code shows in the header on my session

If InStr(MyMessage, "I'") <> 0 Then

I have written a visual basic macro in Excel
I am looking for the strings I'm I'll I'd
Coding as above using "I'" bypasses the text

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Dave Kreskowiak · Answer 1 · 2019-02-26T15:44:00

Definitely not a compiler bug. VBA has been around for decades so that possibility is extremely remote and you're not doing anything "on the edge".

This works as expected for me:

VB.NET

Private Sub Worksheet_SelectionChange(ByVal Target As Range)
Dim message

    message = "I'm OK"
    
    If InStr(message, "I'") <> 0 Then
        MsgBox "Found"
    Else
        MsgBox "Not Found"
    End If
End Sub

Have you used "Option Compare" at the top of your code?

Maciej Los · Answer 2 · 2019-02-26T20:31:00

Well... Replace double quotation marks with single, so ""I'll"" should be replaced with "I'll" and everything will be fine. See:

VB

Option Explicit


Sub test()
    Dim Strings2Find As Variant
    Dim Text2SearchIn As String
    Dim i As Integer, j As Integer
    
    Text2SearchIn = "I'm glad i can see you. I'd like to introduce some one to you. I'll be very happy, if you'll..." 'text is not important ;)
    Strings2Find = Array("I'm", "I'll", "I'd")
    
    
    For i = LBound(Strings2Find) To UBound(Strings2Find)
        Do
            j = InStr(j + 1, Text2SearchIn, Strings2Find(i))
            If j > 0 Then MsgBox "'" & Strings2Find(i) & "' has been found on position: " & j & vbCr & _
            "'" & Text2SearchIn & "'", vbOKOnly, "Success!"
        Loop While j > 0
    Next


End Sub

If instr(mymessage, "I'") <> 0 then = compiler bug ?

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