How to call java script function from PHP

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Can any one help me in calling java script function from PHP

JavaScript

<script>
function HideDiv(id)
{
  document.getElementById(id).style.display="block";				
}

</script>

PHP

if($Acidity=="Acidity")
{
        echo"Raj";	
	echo "<SCRIPT LANGUAGE='javascript'>HideDive('Acidity');</SCRIPT>";

}

I need to make the Div Visible.

Thanks!

Posted 15-Dec-10 2:32am

Rajesh Yerramsetti

Updated 15-Dec-10 2:58am

Abdul Quader Mamun

v3

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Abdul Quader Mamun 15-Dec-10 8:58am

Use pre tag.

Manfred Rudolf Bihy 17-Dec-10 13:32pm

Have you checked my answer yet?

2 solutions

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Manfred Rudolf Bihy · Answer 1 · 2010-12-15T03:25:00

Hi Rajesh,

since the pre tag with attribute lang equal to php seems to make some unwanted modifications concerning double quotes I'll post my answer with lang equal to text (not so nicely fomatted but what you read is what I wrote :) ):

JavaScript

<script type="text/javascript">
function HideDiv(id)
{
    document.getElementById(id).style.display="block";
}
</script>

if($Acidity=="Acidity")
{
    echo "Raj";
    echo "<script type='text/javascript'>HideDiv('Acidity');</script>";
}

There are two issues I found in your code:
1. Script tag's attribute to select scripting lanuage is called type
and takes "text/javascript" for javascript code.
2. Function you wrote is named HideDiv(id) you called a function called HideDive(id).

I hope you get it to work with these corrections!

Best Regards,

Manfred

PS: The function should be called ShowDiv if its semantic is to reveal the div and not to hide it.

ahmadnawaz · Answer 2 · 2010-12-27T20:22:00

Solution 2

try the following code.

PHP

if($Acidity == 'Acidity')
{
echo "Raj";
echo "<Script language='text/javascript'">Hidediv('Acidity');</Script>";
}

I hope this will correct your code.

Posted 27-Dec-10 20:22pm

ahmadnawaz

Updated 27-Dec-10 20:26pm

v3

Comments

Dalek Dave 28-Dec-10 2:26am

Edited for Code Block.