save and show image for the database

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Dear sir\mam

I am fresher web developer in asp.net with C# .I want to show image and save it in a database. This is my code .
But there one Error in this code . Error is that:
("Must declare the scalar variable "@Img".Must declare the scalar variable "@@ImgID" ").
Please help any one and any other simple way of save image and show it.

Thank's in advance

C

public class ShowIamge : IHttpHandler
{
    SqlConnection con = new SqlConnection();
    SqlCommand cmd = new SqlCommand();
    
    public void ProcessRequest(HttpContext context)
    {
        Int32 Id1;
        if (context.Request.QueryString["ImgID"] != null)
            Id1 = Convert.ToInt32(context.Request.QueryString["ImgID"]);
         else
        throw new ArgumentException("No parameter pecified");           
        context.Response.ContentType ="image/jpeg";
        Stream strm = ShowImage(Id1);
        byte[] buffer = new byte[4096];
        int byteSeq = strm.Read(buffer,0, 4096);
          while (byteSeq > 0)
        {
            context.Response.OutputStream.Write(buffer, 0, byteSeq);
            byteSeq = strm.Read(buffer, 0, 4096);
        }
    }
    public Stream ShowImage (int Id1)
    {
        SqlConnection con = new SqlConnection(); 
con =new SqlConnection("Server=PC-5\\SQLEXPRESS; database=imagedate; Integrated Security=True");  
        string sql =("Select Image From image where ImgID=@Id1");
        cmd = new SqlCommand(sql,con);
        cmd.CommandType=CommandType.Text;   
        cmd.Parameters.AddWithValue("@ImgID",Id1);
        con.Open();     
        object img = cmd.ExecuteScalar();

     try
        {
            return new MemoryStream((byte[])img);
        }
        catch
        {
            return null;
        }
        finally
        {
            con.Close();
        }
    }
  public bool IsReusable
    {
       get
        {
        return false;
        }
   }
 }
 protected void Btnok_Click1(object sender, EventArgs e)
    {
        con = null;
        con = new SqlConnection("Server=PC-5\\SQLEXPRESS; database=imagedate; Integrated Security=True");
        con.Open();
        FileUpload img = (FileUpload)imgUpload;
        Byte[] imgByte = null;
        if (img.HasFile && img.PostedFile != null)
        {
            HttpPostedFile File = imgUpload.PostedFile;
            imgByte = new Byte[File.ContentLength];
            File.InputStream.Read(imgByte, 0, File.ContentLength);
        }
        string sql = "INSERT INTO image (Image) VALUES (@Img) SELECT @@ImgID";
        SqlCommand cmd = new SqlCommand(sql, con);
        cmd.Parameters.AddWithValue("@Image", imgByte);
        //cmd.Parameters.AddWithValue("@name", txtEName.Text);
        int ImgID = Convert.ToInt32(cmd.ExecuteScalar());
        con.Close();
       Image1.ImageUrl = "~/ShowIamge.ashx?ImgID=" + ImgID; 
    }

Posted 27-Dec-10 20:47pm

shailendra from MP

Updated 22-Dec-18 6:06am

Tarun.K.S

v2

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Tarun.K.S 28-Dec-10 3:01am

Wrap your code with the <pre> </pre> tags.

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Al-Farooque Shubho · Answer 1 · 2010-12-27T21:01:00

In order to insert a row into the database and get the newly inserted ID, you need to execute the following steps:

1. Use cmd.ExecuteNonQuery() to execute insert operation (Instead of ExecuteScaler().

2. Execute another SQL statement "SELECT SCOPE_IDENTITY()" and use ExecuteScaler() to get the newly inserted ID.

I would recommend you to create a Stored Procedure to carry out the overall task. Following is a very simple stored procedure which does that:

SQL

CREATE PROCEDURE dbo.SAVE_TEMPLATE(
    @Id INT
    , @Name varchar(255)
    , @GeneratedID INT OUTPUT
)
AS
BEGIN
        -- New Record, So insert it into the dbo.Templates
        INSERT INTO dbo.Table (Name)
        VALUES(@Name);
        SET @GeneratedID = SCOPE_IDENTITY();
END

Hope this helps.

Member 11332597 · Answer 2 · 2018-12-22T06:06:00

DEAR I WAS HAVING SAME PROJECT AND SAME ISSUE BUT I SOLVED IT. YOU CAN ALSO TRY COPY AND PASTE MY CODE IN "INSERT BUTTON"

SqlCommand command = new SqlCommand("INSERT INTO  myimages(id,name,description,image)VALUES('" + textBoxID.Text + "','" + textBoxNAME.Text + "','" +textBoxdescription.Text + "',@img) ", connection);
            command.Parameters.Add(new SqlParameter("@img", img));
            connection.Open();
            if(command.ExecuteNonQuery() == 1)
            {
                MessageBox.Show("Data Inserted Successfully");
            } else
           {
               MessageBox.Show("Query not Executed");
           }
           connection.Close();

save and show image for the database

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