How to select data order by the condition depending on the count of space(" ") in result in SQL statement

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Hello,
I want to select values that start with some value and order by the number of space containing in the result.
I means...
If I want to find key word "go" and then,
results may be... "go after","go and leave","go", etc...
and I want to get result as
"go and leave", (having 3 spaces)
"go after, (having 2 spaces)
"go" (having 1 space)

How can I write my query from this,
SELECT * FROM [table1] WHERE [column1] LIKE 'go%' ORDER BY...?
If I can't retrieve data using order by command only, Is there any way to execute in sql only such as writing SQL function in stored procedure. Thanks alots.

Posted 6-Apr-11 1:34am

whitehaker

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Dylan Morley · Accepted Answer · 2011-04-06T01:42:00

Solution 1

Have a look at this question that looks like it'll do what you need

http://www.dotnetspider.com/forum/156982-How-count-blank-space-using-sqlserver.aspx[^]

Posted 6-Apr-11 1:42am

Dylan Morley

Comments

whitehaker 6-Apr-11 7:47am

Thanks..

Mahendra.p25 · Accepted Answer · 2011-04-06T02:16:00

Solution 2

try this

SQL

SELECT Name, LEN(Name)- LEN(REPLACE(Name ,' ','')) [CNT]
FROM test5 order by CNT desc

Posted 6-Apr-11 2:16am

Mahendra.p25

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whitehaker 7-Apr-11 5:15am

Thanks for your help.