Datalist SelectField or HyperlinkField to get item details url?

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Hello,
I'm trying to place select hyperlink, or button to get item details on another page. In DataGrid control it is very easy to do it, I have just add HyperLinkField, and add Url parameter details.aspx?id={0}.

I have tried with below code, but of course it is not working, as getting error:
"Input string was not in a correct format"

XML

<asp:HyperLink  id="HyperLink1" runat="server" navigateurl="details.aspx?id={0}"> Details</asp:HyperLink>

Thank you in advance for help to anyone.

Posted 10-Apr-11 2:11am

DejanDejanovic

Updated 10-Apr-11 17:40pm

Chris Maunder773.4K

v2

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3 solutions

Solution 1

Alternative is, the <asp:gridview xmlns:asp="#unknown"> tag have the attribute setting AutoGenerateSelectButton=true and OnSelectedIndexChanged="selectedIndex_Changed", on the server side

C#

protected void selectedIndex_Changed(object sender, EventArgs  e)
        {

            int selectedIndex=((GridView )sender).SelectedIndex
        }

using the selectedIndex, you can get the id value and have redirect command.

or Send me your code.

Posted 10-Apr-11 15:57pm

Ramu Sangabathula Original

Comments

m@dhu 11-Apr-11 0:32am

I think OP is asking about DataList control.

Solution 3

Thanks guys for replies. As I'm using vb.net, I will took last solution.

Posted 11-Apr-11 8:06am

DejanDejanovic

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m@dhu · Accepted Answer · 2011-04-10T18:31:00

Solution 2

<asp:HyperLink  id="HyperLink1" runat="server" navigateurl='details.aspx?id=<%# Eval("IDfield") %>'> Details</asp:HyperLink>

Posted 10-Apr-11 18:31pm

m@dhu