How i can extract attachment file from MessageRaw in OpenPOP library

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Hi I use OpenPOP library for Send and Recive Email.
A part of my program is save recived email to database.
In another part of my program i must show attachment files that saved into database to user.
In my save method, i save RawMessage (include headers, sender, attachments and etc) into database.

C#

var MailContent = GetMessage(MessageNumber);
DB.RawMessage = (from a in MailContent.RawMessage
                 select (byte)a).ToArray();

.
.
.
//finaly save DB into Database

Now my question is: How i can extract attachment files from saved RawMessage?

Posted 13-Apr-11 22:34pm

kia.sos

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2 solutions

Solution 1

Hi, check this blog[^] for the code on attachment.

Something like

OpenPOP.MIMEParser.Message msg = MailContent.GetMessage(x, false);
if (msg != null) {
   for (int y = 0; y < msg.AttachmentCount; y++) {
      Attachment attachment = (Attachment)msg.Attachments[y];
      
      if (string.Compare(attachment.ContentType, "text/xml") == 0) {
         System.Xml.XmlDocument doc = new System.Xml.XmlDocument();
         string xml = attachment.DecodeAsText();
         doc.LoadXml(xml);
         doc.Save(@"C:\POP3Temp\test.xml");
      }
   }
}

Posted 13-Apr-11 23:35pm

Pong D. Panda

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kia.sos · Accepted Answer · 2011-04-15T19:22:00

Hi Thank you for your response.
I solve my problem with below code:

First creat a message object from OpenPOP.Mime.Message:

C#

string StringRawContent = System.Text.ASCIIEncoding.ASCII.GetString(DB.RawMessage.ToArray());
OpenPOP.MIME.Message raw = new OpenPOP.MIME.Message(true, StringRawContent, false);

Now we have all parts of email such as Subject, Body, Sender, Attachments and etc in raw object.
For example i get first attachment file via below code:

C#

if (raw.Attachments.Count > 0)
    AttachmentFileContent = (from a in raw.Attachments.First().RawContent
                             select (byte)a).ToArray();