C# Knowing the corners

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C#

How do i make it know the location of each corner of my form?

Posted 8-May-11 21:24pm

C.CoderCreator

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[no name] 9-May-11 3:35am

How do I make me know what you want?

Thomas Krojer 9-May-11 3:38am

the question was clear

[no name] 9-May-11 3:41am

Really? You do know what 'it' is, that's supposed to know a form's corners?

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Sergey Alexandrovich Kryukov · Answer 1 · 2011-05-08T21:37:00

Solution 3

These are defined by Top, Bottom, Left, Right. For inner corners, use the same properties of the ClientRectangle, but remember it's int the different coordinates — relative to form's Location.

—SA

Posted 8-May-11 21:37pm

Sergey Alexandrovich Kryukov

Comments

Espen Harlinn 9-May-11 16:49pm

My 5 :)

Sergey Alexandrovich Kryukov 9-May-11 21:40pm

Thank you, Espen.
--SA

Tarun.K.S · Answer 2 · 2011-05-08T22:20:00

Solution 4

I tried in this way:

C#

Point LocXY = this.Location;

MessageBox.Show("Top left corner location: " + LocXY.X + "," + LocXY.Y);
MessageBox.Show("Bottom Right corner location: " + (LocXY.X + this.Width) + "," + (LocXY.Y + this.Height));
MessageBox.Show("Bottom left corner location: " + LocXY.X + "," + (LocXY.Y + this.Height));
MessageBox.Show("Top right corner location: " + (LocXY.X + this.Width) + "," + LocXY.Y);

These message boxes are annoying but you can use the result in the way you like.

Hope it helped.

Posted 8-May-11 22:20pm

Tarun.K.S

Comments

Espen Harlinn 9-May-11 16:49pm

Nice effort, my 5

Tarun.K.S 10-May-11 2:32am

Thanks!

Sergey Alexandrovich Kryukov 11-May-11 23:08pm

Correct, 5.
--SA

Tarun.K.S 12-May-11 2:00am

Thanks SA!

Wayne Gaylard · Answer 3 · 2011-05-08T21:34:00

Solution 1

You can use the Location property of your form to get a Point containing the screen coordinates of the form.

Hope this helps

Posted 8-May-11 21:34pm

Wayne Gaylard

Thomas Krojer · Answer 4 · 2011-05-08T21:36:00

Solution 2

You can use the

Location<br />

and

Size

Properties.

The best would be you read this: http://msdn.microsoft.com/en-us/library/aa984420%28v=vs.71%29.aspx[^]

Posted 8-May-11 21:36pm

Thomas Krojer