string myXMLfile = @"C:\MySchema.xml";
DataSet ds = new DataSet();
System.IO.FileStream fsReadXml = new System.IO.FileStream
(myXMLfile, System.IO.FileMode.Open);
try
{
ds.ReadXml(fsReadXml);
datalist.DataSource = ds;
}
catch (Exception ex)
{
MessageBox.Show(ex.ToString());
}
Hope this can help you.