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I have the following password rules. I need regular expression for this.

Please follow the following password rules:
a.Minimum Password Length is 8
b.Minimum Numeric Character is 1
c.Minimum Alphabet Character is 2
d.Any Special Characters can access

Theigi Win
Theingi Win 15-Jun-11 23:49pm    
Thanks for your Answers! Now i solved it.
Best Regards,
Theingi Win

Try this:
char[] cArray = textBox1.Text.ToCharArray();
int length = cArray.Length;
bool hasDigit = cArray.Any(c => char.IsDigit(c));
int alphabetCount = cArray.Count(c => char.IsLetter(c));
int specialCharCount = cArray.Count(c => !char.IsLetterOrDigit(c));

Hope this helps!
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try this :-

private void button1_Click(object sender, EventArgs e)
            StringBuilder sb = new StringBuilder();
            string str = textBox1.Text.Trim();
            int noOfChr = 0;
            int noOfNo = 0;
            for (int i = 0; i < str.Length; i++)
                if (char.IsLetter(str[i]))
                    noOfChr = noOfChr + 1;

                else if (char.IsDigit(str[i]))
                    noOfNo = noOfNo + 1;

            if (noOfNo < 1) { MessageBox.Show("Enter minimum 1 Digit !!"); return; }
            if (noOfChr < 2) { MessageBox.Show("Enter minimum 2 Alphabet !!"); return; }

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Theingi Win 15-Jun-11 23:48pm    
Thanks! Rajesh Lagria
I think Regular Expression is not the best tool here, because your requirements don't present any regular pattern; all the listed features can be mixed in all possible combinations.

The problem is easy-to-solve. Consider your requirements as pseudo-code and your 'a'-'d' items as separate predicates. Make your pseudo-code into real code by counting each feature. In this way, you could even return a string reporting all disadvantaged about user's password candidate to the user item by item. With Regular Expression this nice feature would be completely impossible.

Write this simple code and ask a question if you face any problems.

Good luck,
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Theingi Win 15-Jun-11 23:48pm    
Thanks! SAKryukov
Sergey Alexandrovich Kryukov 17-Jun-11 22:37pm    
You're very welcome.
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Thank you.

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