how to make visible by function name of form

Question

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i have a menu bar and their items are
item1
item2
item3
.
.
.

initally all items visibility is false

in an arraylist these items are saved

e.g.
in arraylist i have item1, item2, item3, ........

C#

for(int i=0; i<arraylist.count; i++) 
   arraylist[i].toString()

now here the string is same as menubar item1
now from this array list i want to change the visibility of items

Posted 3-Aug-11 21:33pm

kami124

Updated 3-Aug-11 21:48pm

walterhevedeich

v4

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Comments

[no name] 4-Aug-11 3:38am

Please reframe your question what you want to ask. and share your code as well.

3 solutions

Solution 1

If your ArrayList contains the items - which it appears to - then just cast them to ToolStripMenuItems and set the appropriate properties.

Or better, don't use an ArrayList, use a List<ToolStripMenuItem> instead, and you won't need to cast it...

Posted 3-Aug-11 21:53pm

OriginalGriff

Solution 2

Try this.

for(int i=0; i<arraylist.count; i++) 
{
  if(arraylist[i].toString() == "item1")
  {
    item1Id.Visible = true;
  }
  else if(arraylist[i].toString() == "item2")
  {
    item2Id.Visible = true;
  }
  else if(arraylist[i].toString() == "item3")
  {
    item3Id.Visible = true;
  }
}

Posted 3-Aug-11 21:53pm

Toniyo Jackson

Updated 3-Aug-11 21:54pm

v2

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UJimbo · Accepted Answer · 2011-08-03T22:02:00

Solution 3

private void formm_display_function(string display_form_str)
{
   try
   {
      if(menuStrip1.Items.ContainsKey(display_form_str))
         menuStrip1.Items[display_form_str].Visible = true;
   }
   catch (Exception ex)
   {
      MessageBox.Show(ex.Message.ToString());
   }
}

Posted 3-Aug-11 22:02pm

UJimbo

Updated 3-Aug-11 23:04pm

v5

Comments

kami124 4-Aug-11 4:10am

ok when this condition will become true
if (ctrl.Length == 1)

UJimbo 4-Aug-11 4:13am

When Contols.Find "finds" at least 1 control having the same name as the item parameter. For example, in my case, I have a listview control on my form named "listview1". Controls.Find will return only 1 control in the ctrl array.

kami124 4-Aug-11 4:15am

here is my actual code check where i make a mistake

private void formm_display_function(string display_form_str)
{

// string[] theArr = new string[] { "listView1" };

// foreach (string item in function_list_display)
for (int i = 0; i < function_list_display.Count; i++)
{
Control[] ctrl = this.Controls.Find(function_list_display[i], false);

if (ctrl.Length == 1)
{
ctrl[0].Visible = true;
}
}
}

kami124 4-Aug-11 4:15am

private void formm_display_function(string display_form_str)
{

for (int i = 0; i < function_list_display.Count; i++)
{
Control[] ctrl = this.Controls.Find(function_list_display[i], false);

if (ctrl.Length == 1)
{
ctrl[0].Visible = true;
}
}
}

UJimbo 4-Aug-11 4:23am

You don't need to use an array list in this function by the looks of it, since you are only supplying a string parameter called display_form_str. If this is correct, just use:

private void formm_display_function(string display_form_str)
{
Control[] ctrl = this.Controls.Find(display_form_str, false);

if (ctrl.Length == 1)
{
ctrl[0].Visible = true;
}
}

kami124 4-Aug-11 4:30am

but still there is some problem
display_form_str="item1"
but in the code this ctrl.Length remains null
i didnt understand how to handle it

UJimbo 4-Aug-11 4:32am

If ctrl.Length is 0, it means it didn't find a control with that name on the form

kami124 4-Aug-11 4:43am

now i did it like this but still its not setting it visible ture

if (display_form_str == "Users1")
Users1.Visible = true;
else
{
if (display_form_str == "Roles2")
Roles2.Visible = true;
else
{
if (display_form_str == "Functions4")
Functions4.Visible = true;
else
{
if (display_form_str == "FunctionA5")
FunctionA5.Visible = true;
else
{
if (display_form_str == "UserMRF")

FunctionB6.Visible = true;
else
messagebox.show("sorry");

UJimbo 4-Aug-11 4:51am

What's the name of your menu bar? I just noticed it's a menu bar and not a control on a winform. Try setting:

yourmenubar.Items["display_form_str "].Visible = true;

kami124 4-Aug-11 4:58am

private void formm_display_function(string display_form_str)
{
menuStrip1.Items[display_form_str].Visible = true;
}

i have done likr this but there is an error

"object reference not set to an instance of an object"

UJimbo 4-Aug-11 5:05am

Updated solution. Make sure you are entering the menustripitem's Name and not Text

kami124 4-Aug-11 5:15am

thank you very much
helping me in such a nice way

UJimbo 4-Aug-11 5:21am

My pleasure kami, take care :)