help in asp.net website

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hi to all,
I am developing a website that have various modules.
It have EMPCODE on various forms as link button.
I want to show employee information on various forms on mouse over on link button using ajax.

>I does not want to design panel on each form for showing employee information.
>is it possible by making a method as in windows application so that i can call it on each form.
if yes how it is possible?

Posted 5-Aug-11 19:42pm

uspatel

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uspatel 7-Aug-11 13:29pm

Please any body suggest some ideas that make above task easy

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thatraja · Answer 1 · 2011-08-07T18:31:00

You may create a DIV dynamically & add your content to that & then you can show that in UI on mouseover.

Dynamically Create a DIV tag using Server-Side code or JavaScript[^]
DIV Popup for the OnmouseOver Event[^]

EDIT
-------------------------------
Consider you have received data in DataTable from database.
So Now your DataTable(dtEmployee) has 1 row based on given EmpCode

C#

if (dtEmployee.Rows.Count > 0)
{
 StringBuilder sb = new StringBuilder();
 sb.AppendLine("Employee Name : <b>" + dtEmployee.Rows[0]["EmployeeName"].ToString() + "</b>");
 sb.AppendLine("DOB : <b>" + dtEmployee.Rows[0]["DOB"].ToString() + "</b>");
 sb.AppendLine("Phone : <b>" + dtEmployee.Rows[0]["Phone"].ToString() + "</b>");
 Div1.InnerHtml = sb.ToString();//Finally assign the dynamic value to the dynamic DIV

}

Change the coding based on your requirement.