Grouping data by interval

Question

0.00/5 (No votes)

See more:

SQL-Server-2008

Dear all,

I have a little question about SQL Server 2008.
This is My Data:

NAME	DUE_IN 	VALUE
----------------------
A	15	15000
B	30	23000
A	45	15200
A	78	45000
C	45	13000
D	10	45700
D	45	45800
A	78	10220
B	10	78900
A	46	98700
A	35	45000

I want to group it into this:

NAME	DUE_IN	  VALUE
A	(<15)	  sum(value)
A	(15-30)	  sum(value)
A	(>30)	  sum(value)
B	(<15)	  sum(value)
B	(15-30)	  sum(value)
B	(>30)	  sum(value)
C	(<15)	  sum(value)
C	(15-30)	  sum(value)
C	(>30)	  sum(value)
D	(<15)	  sum(value)
D	(15-30)	  sum(value)
D	(>30)	  sum(value)

How can i do that.. I have no idea at all.. :(

Posted 16-Oct-11 23:25pm

Dwi Prawira

Add a Solution

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Om Prakash Pant · Answer 1 · 2011-10-17T01:12:00

one option is as follows:
>
SQL

select namee, '(<15)', sum(vvalue) from #te where due_in <= 15 group by namee union select namee, '(15-30)', sum(vvalue) from #te where due_in between 15 and 30 group by namee union select namee, '>30', sum(vvalue) from #te where due_in > 30 group by namee

Maciej Los · Answer 2 · 2016-01-06T06:57:00

Check this:

SQL

CREATE TABLE TestData
(
  [NAME] VARCHAR(10),
  DUE_IN INT,
  [VALUE] INT
)

INSERT INTO TestData ([NAME], DUE_IN, [VALUE])
VALUES('A', 15, 15000),
('B', 30, 23000),
('A', 45, 15200),
('A', 78, 45000),
('C', 45, 13000),
('D', 10, 45700),
('D', 45, 45800),
('A', 78, 10220),
('B', 10, 78900),
('A', 46, 98700),
('A', 35, 45000)

DECLARE @tmp TABLE(RangeId INT IDENTITY(1,1), RangeName VARCHAR(10), RangeMin INT, RangeMax INT)

INSERT INTO @tmp (RangeName, RangeMin, RangeMax)
VALUES('>15', 0, 14),('15-30', 15, 30), ('>30', 31, 999999)

SELECT t1.[Name], t2.RangeName AS DUE_IN, SUM(t1.[Value]) AS [SumOfValue]
FROM TestData As t1 
    INNER JOIN @tmp AS t2 ON t1.[DUE_IN]>=t2.RangeMin AND t1.[DUE_IN]<=t2.RangeMax
GROUP BY t1.[Name], t2.RangeName, t2.RangeId
ORDER BY t1.[Name], t2.RangeId

Result:

Name 	DUE_IN 	SumOfValue
A 	15-30 	15000
A 	>30 	214120
B 	>15 	78900
B 	15-30 	23000
C 	>30 	13000
D 	>15 	45700
D 	>30 	45800

SQL Fiddle[^]

Grouping data by interval

2 solutions

Solution 1

Solution 2

Add your solution here

Preview 0