Why data is not going to data base table

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C#

private void button1_Click(object sender, EventArgs e)
        {
            string connetionString = null;
            SqlConnection cnn ;
           connetionString = "Data Source=JDPANDEY-PC;Initial Catalog=Janardan;User ID = sa;Password= 123";
            cnn = new SqlConnection(connetionString);
            try
            {
                cnn.Open();     
                MessageBox.Show ("Connection Open ! ");
               
               string insertString = @" insert into emp values ('" + textBox1.Text.Trim () + "','" + textBox2.Text .Trim() + "','" + textBox3.Text.Trim() + "','"+ textBox4.Text.Trim() +"')";
                              
cnn.Close();
            }
            catch (Exception ex)
            {
                MessageBox.Show("Can not open connection ! ");
            }

Posted 4-Dec-11 23:23pm

Janardan Pandey

Updated 4-Dec-11 23:25pm

uspatel

v2

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Karthik Harve 5-Dec-11 5:25am

how many columns does the emp table has..??? and all columns are of type varchar or char..??

4 solutions

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Eduard Lu · Answer 1 · 2011-12-04T23:27:00

Solution 1

Because you just assigned your INSERT query in a string variable and never used it.

-Eduard

Posted 4-Dec-11 23:27pm

Eduard Lu

uspatel · Answer 2 · 2011-12-04T23:28:00

Solution 2

You shoul also use these lines of code

C#

SqlCommand cmd = new SqlCommand(insertstring, cnn);
            
            cmd.CommandType = CommandType.Text;
            
            cmd.ExecuteNonQuery();
            cnn.Close();

Posted 4-Dec-11 23:28pm

uspatel

Updated 4-Dec-11 23:29pm

v2

S.P.Tiwari · Answer 3 · 2011-12-04T23:32:00

C#

string insertString =" insert into emp values ('" + textBox1.Text.Trim () + "','" + textBox2.Text .Trim() + "','"+ textBox3.Text.Trim() + "', '" + textBox4.Text.Trim() + "')"

C#

SqlCommand ScalarCommand = new SqlCommand();
            try
            {
                ScalarCommand.CommandText = insertString;
                ScalarCommand.Connection = Cnn;
ScalarCommand.ExecuteScalar();

use above code.
make sure all datatype of database is matches with insert value.

Pratik.Patel · Answer 4 · 2011-12-07T23:21:00

Solution 4

You actually need to create a valid SqlCommand object and execute the command on database with a valid open connection associated with it.

Posted 7-Dec-11 23:21pm

Pratik.Patel