How to popup window in C#

in form 1 button click event enter the following code

{
form2 frm = new form2(); //it will initialize the object frm for form 2 in form 1
frm.Show();// this will opening form 2

//if you want to hide form 1 then
this.Hide();
}

try this.

inside the button_Click event,

form2.show();

hope it helps

don't forget to vote

thank

first u have to create object of form 2 in form1 .cs
then call show method of form 2

in form1.cs

on buttin click method


{
form2 frm = new form2(); // object of form 2
frm.Show() // it will pop up your form 2
}

Please mark as answer and vote





<ajax:modalpopupextender id="ModalPopupExtender1" runat="server" targetcontrolid="btnShowModalPopup" xmlns:ajax="#unknown">
PopupControlID="panelDragHandle" BackgroundCssClass="modalBackground" OkControlID="btnOk">

<asp:panel runat="server" id="panelDragHandle" cssclass="modalPopup" width="70%" xmlns:asp="#unknown">

<asp:button id="btnOk" runat="server" text="Ok">



In c#:

if (e.CommandName == "Popup")
{
LinkButton id = (LinkButton)e.Item.FindControl("LinkButton1");
string custID = id.Text;
ModalPopupExtender1.Show();

}