Making a never-ending loop of queued functions in JQuery

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Hi everyone,

I have a javascript script running in one of my webpages. In this script I have 8 functions running one after another, in order.

My question is, is there a way of looping this queue of functions, so that is constantly runs, in the same order that it first runs?

Any replies are most appreciated,
Tom.

Posted 22-Feb-12 2:02am

thomasriley

Updated 22-Feb-12 2:57am

Eduard Keilholz

v2

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3 solutions

Solution 3

Thankyou Eduard and Martin both your solutions work fine!

Tom.

Posted 5-Mar-12 1:35am

thomasriley

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Eduard Keilholz · Accepted Answer · 2012-02-22T02:56:00

Why don't you call the next function on the last line of code in the 'current' function?

var myFunctions = {
    one: function(){
        myFunctions.two();
    },
    two: function(){
        myFunctions.three();
    },
    three: function(){
        myFunctions.four();
    },
    four: function(){
        myFunctions.one();
    }
}

$(document).ready(function(){ myFunctions.one(); });

But than ofcourse with eight functions in stead of four.

Good luck!

Martin Arapovic · Accepted Answer · 2012-02-22T04:34:00

Solution 2

hi,

Here[^] is a contribution to Eduard's answer...

Another solution is to make an array of your functions and the use jquery each and setTimeout to call them one by one...

Posted 22-Feb-12 4:34am

Martin Arapovic