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Hi everyone,
Is it possible to use such a data structure List<T>[][] listArray
Let me explain in more detail. For example when we use string[][] strArray and
strArray[i][j] gives us a string. Is there any way to do this with List<T>.
i.e ListArray[i][j] should give me a list ? (dictionary may solve my problem but I wonder if there is another way. )
Updated 8-Oct-20 1:24am
Shahin Khorshidnia 27-Feb-12 16:49pm    
Creating Your Own Collection Class!
Sander Rossel 27-Feb-12 17:37pm    
Actually I have written an article about implementing your own collections (including a Dictionary). If you're interested you can read it. Find it at my articles, it's called 'Having fun with custom collections!' :)
Shahin Khorshidnia 27-Feb-12 18:07pm    
Of course I'll read it.

How about a List<List<T>>? :)
I guess having a list of lists is more or less the same as having a two-dimensional array.
List<T>[][] is also perfectly valid, although you'd get a lot of lists.
List<List<string>> lists = new List<List<string>>();
string test = lists[0][0]; // Should return "Hello".

So about the Dictionary<TKey, TValue>[^] option, you could have a Dictionary inside a Dictionary.
You say you have a day, so let's say day 1, day 2, day 3... In this case a day is an integer value.
For any given day you have a time, perhaps you are using TimeSpan[^] for this.
Also, my guess is that for every day-time combination you want to store a value, let's say a string (but it could be anything). You would then have a Dictionary like this:
Dictionary<int, Dictionary<TimeSpan, string>>
string myString = myDictionary[1][myTime] // Day 1 at that specific time.
Let's say your day is a specific date. Your Dictionary would then look like:
Dictionary<DateTime, Dictionary<TimeSpan, string>>
string myString = myDictionary[DateTime.Today][myTime] // Today at that specific time.
Usage is pretty easy compared to working with a multidimensional array I think (but that's just a matter of what you're accustomed to) :)
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Sergey Alexandrovich Kryukov 27-Feb-12 16:48pm    
This is a valid suggestion, my 5, but formally one can use List<T>[][] (array of arrays of instances of List<T>) or anything like that.
Sander Rossel 27-Feb-12 16:53pm    
Thanks! Sure you can use it, but it's not the easiest method (well, if you're not used to (multi-dimensional) arrays) :)
mstk_ 27-Feb-12 16:53pm    
Thank you for quick reply. But as I said above lists[0][0] should return me a list not a string. Because I want to use days as colums and times(9:00-18:00) as rows. But you say "List<t>[][] is also perfectly valid". I'll try it soonest I hope it makes my job easier. :)
Sander Rossel 27-Feb-12 16:57pm    
You could also try Dictionary<int, Dictionary<TimeSpan, string>>
You could then say: string myString = myDictionary[1][myTime]
wizardzz 27-Feb-12 16:59pm    
Look at SAK's suggestion then.
You can use (data_type array_name [][]=new data_type [rows_size][cols_size])
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I guess below explanation works for my requirement which is a kind of two dimentional list array.

In a "Tab control" Every "TabPage" should have one browser which means
TabPage1--> Browser1
TabPage2--> Browser2

Solution (which helps in simulating two dimensional list array):-

Step 1:- Creating a struct
struct myoownobjects
Tabpage tbp
geckofx gkbrw

Step 2:- Creating list array(single dimension) of strcut object

List<myoownobjects> lst1 = new List<myoownobjects>();

I guess this might also work.
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If you know how many lists you will be needing then how about like array[NameList,AgeList,PointList]? The lists can change dynamicly anyway
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