why the address of function is changed if i print it with cout and printf?

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In this code if i write the printf statement then the address appears to be like 4324231 but if i want to print the address of function using cout statement then it prints the address of function as 1 , why the address is changed if i print it with cout and printf?

C++

int main()
{
    int fun();
    
    //printf("%d",&fun);
    cout<<(&fun);
    getch();
    return 0;
}

int fun()
{
}

Posted 3-Mar-12 18:05pm

Ashutosh_g

Updated 3-Mar-12 18:06pm

RaisKazi

v2

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Cashey Wen · Answer 1 · 2012-03-03T18:49:00

The statement "cout<<(&fun);" will treat (&fun) as a boolean value. The address of func is casted to bool (always evaluate as `true' ), then it is output as "1".

C++

#include <iostream>
#include <conio.h>
using namespace std;

int fun();

int main()
{
    int fun();

    printf("%x\n",&fun);
    cout<<(void*)(&fun);
    getch();
    return 0;
}

int fun()
{
    return 0;
}