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I wanted to ask how do we write this program to calculate the average test score of a 5 student

·Input: file containing 5 student’s first name, last name, five test scores

·Output: file containing 5student’s first name, last name, five test scores, average of five test scores


I have try it but all i get is errors..

I'm using NetBeans IDE 7.1 program..

------------------------------------------------------------------------------------------------

EDIT: Let's bring the code up here, it's more readable here:

Java
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.PrintWriter;
import java.util.Scanner;
public class Homework {

    public static void main(String[] args)throws FileNotFoundException    {   

        Scanner inFile = new Scanner(new FileReader("FiveTestScores.txt")); 

        PrintWriter outFile = new PrintWriter("FiveTestScoresAverage.out");

            String firstname;            
            String lastname;

            int test1, test2, test3, test4, test5;            
            double average;

            firstname = inFile.next(); // get the first name

            lastname = inFile.next();  // get the last name

            test1= inFile.nextInt();             
            test2= inFile.nextInt(); 
            test3= inFile.nextInt();             
            test4= inFile.nextInt(); 
            test5= inFile.nextInt(); 

           System.out.println("Student Name: " + firstname + " " + lastname);

           System.out.printf("Test scores: %2d %2d %2d " + "%2d %2d ", test1, test2, test3, test4, test5);

           average = (test1 + test2 + test3 + test4 + test5) /5.00;

           System.out.printf("\nAverage of test scores:%5.2f" , average);

           inFile.close();    	    
           outFile.close();    
   }
}


if i do this steps 5 times it become an error..I want to why is that..

and how I could do it for 5 student.....

also it says that i can't write inFile.nextInt(); a lot of times... Why is that??

What can I do??
Posted
Updated 13-Mar-12 3:40am
v5
Comments
Prasad_Kulkarni 13-Mar-12 2:15am    
can you post your code which you have tried..
TorstenH. 13-Mar-12 4:04am    
I added a homework tag - cause that's what it is.
Please ask specific questions to your code.

We will help, but we do not do homework.
Richard MacCutchan 13-Mar-12 6:01am    
Show the code and, more importantly, the errors.
MysteriousAmber 13-Mar-12 9:09am    
This is the right code..package homework; import java.util.*;

import java.io.*;public class Homework {

public static void main(String[] args)throws FileNotFoundException {

Scanner inFile = new Scanner(new FileReader("FiveTestScores.txt"));

PrintWriter outFile = new PrintWriter("FiveTestScoresAverage.out");

String firstname; String lastname;

int test1, test2, test3, test4, test5; double average;

firstname = inFile.next(); // get the first name

lastname = inFile.next(); // get the last name

test1= inFile.nextInt(); test2= inFile.nextInt();

test3= inFile.nextInt(); test4= inFile.nextInt();

test5= inFile.nextInt();

System.out.println("Student Name: " + firstname + " " + lastname);

System.out.printf("Test scores: %2d %2d %2d " + "%2d %2d ", test1, test2, test3, test4, test5);

average = (test1 + test2 + test3 + test4 + test5) /5.00;



System.out.printf("\nAverage of test scores:%5.2f" , average);

inFile.close(); outFile.close(); }}

if i do this steps 5 times it become an error..I want to why is that..

and how I could do it for 5 student.....

also it says that i can't write inFile.nextInt(); a lot of times... Why is that??

What can I do??

1 solution

OK, these are questions. +5 for that.

- you should probably use loops on this task, it literally demands for them:
reading students until no more students are available -> while loop
reading 5test scores for a student -> for loop

- figuring the average value is a top task for an own method with a return value. You should divide the sum with the number of test scores - that's more valid. the result will be a double value even if the sum is given as a int.
 
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Comments
MysteriousAmber 13-Mar-12 10:28am    
Thanks a lot ^__^
MysteriousAmber 13-Mar-12 13:53pm    
what does this mean??

Exception in thread "main" java.util.InputMismatchException
at java.util.Scanner.throwFor(Scanner.java:909)
at java.util.Scanner.next(Scanner.java:1530)
at java.util.Scanner.nextInt(Scanner.java:2160)
at java.util.Scanner.nextInt(Scanner.java:2119)
at homework.HomeWork.main(HomeWork.java:30)
Java Result: 1
TorstenH. 13-Mar-12 15:26pm    
you have a missmatch in the input - the int values are probably not OK.
solution:
Read value as String and convert by using Integer.parseInt(String). That one throws a NumberFormatException when the value is not ok (I don't know if you're already into Exceptions, but the Netbeans IDE will help you on this task.).

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