How to display the result

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Hi everyone,

I'm new in C I use visual studio 2010, I don't know how to display my output result, I've tried to use printf, but it failed, the result is not indicate the truth of calculation in my program.
Attached link is my project code.
it related with anisotropic filtering.
thanks in advance

http://www.sendspace.com/file/b2qs96[^]

[EDIT: Bring code from answer to question]

below a brief of my code :

main.cpp :

C++

#include <stdio.h>
#include <stdlib.h>
#include "anisodiff1D.h"
#include "anisodiff1D_initialize.h"
#include "anisodiff1D_terminate.h"
#include "rt_nonfinite.h"
#include "anisodiff1D.h"
#include "power.h"
#include "conv.h"
   
 int main(void)
 {
		real_T diff_sig_data[10];
		int32_T diff_sig_sizes[1];
        anisodiff1D_initialize();
		anisodiff1D(diff_sig_data,diff_sig_sizes);  
		anisodiff1D_terminate();
        system ("PAUSE");
        return 0;
 }

anisodiff1D.cpp :

C++

/* Include files */
#include "rt_nonfinite.h"
#include "anisodiff1D.h"
#include "power.h"
#include "conv.h"

void anisodiff1D(real_T diff_sig_data[11], int32_T diff_sig_sizes[1])
{
  static const real_T b_sig[11] = { 10,10,11,10,9,10,13,10,10,13,9 };
 

  int32_T t;
  int32_T nablaW_sizes;
  real_T nablaW_data[11];
  int32_T nablaE_sizes;
  real_T nablaE_data[11];
  real_T b_nablaW_data[11];
  real_T b_nablaE_data[11];
  int32_T tmp_sizes;
  real_T tmp_data[11];
  int iteration=5;
  int kappa=5.0;
 
  diff_sig_sizes[0] = 11;
  memcpy((void *)&diff_sig_data[0], (void *)&b_sig[0], 11U * sizeof(real_T));
  //real_T signal=diff_sig_data[nablaE_sizes];

  /*  Anisotropic diffusion. */
  for (t = 0; t < iteration; t++)  //loop as long as number iteration
  {
    conv(diff_sig_data, diff_sig_sizes, nablaW_data, *(int32_T (*)[1])&nablaW_sizes); //do the convolution to distinguish between edge end not
    b_conv(diff_sig_data, diff_sig_sizes, nablaE_data, *(int32_T (*)[1])&nablaE_sizes);
 
    /*  Diffusion function. */
 
    nablaW_sizes = 11;
    for (nablaE_sizes = 0; nablaE_sizes < 11; nablaE_sizes++) // the coefficient
	{
      b_nablaW_data[nablaE_sizes] = nablaW_data[nablaE_sizes] / kappa;
      b_nablaE_data[nablaE_sizes] = nablaE_data[nablaE_sizes] / kappa;
    }
 
	// function to get exp(-(nablaW/kappa).^2)
    power(b_nablaW_data, *(int32_T (*)[1])&nablaW_sizes, tmp_data, *(int32_T (*)[1])&tmp_sizes);
    nablaE_sizes = 11;
    power(b_nablaE_data, *(int32_T (*)[1])&nablaE_sizes, b_nablaW_data, *(int32_T (*)[1])&tmp_sizes);
 
	/*  Discrete PDE solution. */
	diff_sig_sizes[0] = 11;
    for (nablaE_sizes = 0; nablaE_sizes < 11; nablaE_sizes++) 
	{
      diff_sig_data[nablaE_sizes] = diff_sig_data[nablaE_sizes] + (1/3) * (((1.0 / (1.0 +tmp_data[nablaE_sizes]) * nablaW_data[nablaE_sizes] + 1.0 / (1.0 +b_nablaW_data[nablaE_sizes]) * nablaE_data[nablaE_sizes]))+(diff_sig_data[0]-diff_sig_data[nablaE_sizes]));
	
printf("%g\n",diff_sig_data);  
    }
		  
  }
 
}

Posted 16-Mar-12 17:05pm

linavaya

Updated 17-Mar-12 2:21am

Nelek

v2

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Comments

Sergey Alexandrovich Kryukov 16-Mar-12 23:17pm

It is not likely that someone will be interested in downloading of the whole RAR file in this indirect way from the unknown source; and relatively big volume of code is hardly adequate to this simple question.

You really should create a simple code sample comprehensively manifesting your problem and post it using "Improve question" above, formatted with "pre" tags. It can really be a few line of code, maybe even one...

--SA

2 solutions

Solution 3

if you are using Visual Studio you don't need that system("pause"); if you want to see your result in the console just press Ctr + F5 and the window wont disappear right away. If you press only F5 the window will flash with the result and you wont be able to see it (like other compilers )

Posted 26-Mar-12 3:23am

Argonia

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nv3 · Accepted Answer · 2012-03-17T06:54:00

The printf statement at the end of your function uses diff_sig_data as argument. This is an array and not a single value. Depending on what you want you should either output a single value, for example:

printf("%g\n", diff_sig_data[0]);

or the entire array by enclosing it in a loop

for (int i = 0; i < 11; ++i)
    printf("%g\n", diff_sig_data[i]);