(C# newbie) Starting processes with "extra settings"?

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Hi! Newbie inquiring help in C# here ^^"

So I'd like to learn if there's a way to start processes with "special settings in the end" (I have no idea what to call it) with C#.

An example of what I mean would be that if you add "-window" at the end of your WarCraft III shortcut target, the game will be run in windowed mode.
(So if you go to properties of the warcraft III shortcut, the target will display '"C:\Games\Warcraft III\Warcraft III.exe" -window')

I hope you understand what I mean, please ask if it's unclear.

Best regards
-Mossmyr

Posted 1-May-12 1:52am

Mossmyr

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3 solutions

Solution 2

You talk about parameters;

System.Diagnostics.Process process = new System.Diagnostics.Process();
process.StartInfo.FileName = @"C:\Games\Warcraft III\Warcraft III.exe";
process.StartInfo.Arguments = "window";
process.UseShellExecute = false;
process.Start();

Posted 1-May-12 2:13am

MisterInspector

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Mossmyr 1-May-12 10:46am

I'm missing the System.Diagnostics.Process.UseShellExecute method (I am using System.Diagnostics).
Not having it there does start the game, but not in windowed mode :/

Solution 3

These settings are called command line arguments. You can get these arguments using Environment.GetCommandLineArgs();[^]

Posted 1-May-12 2:14am

Pete O'Hanlon

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OriginalGriff · Accepted Answer · 2012-05-01T02:11:00

Solution 1

Yes - it's the parameters, or program arguments:

C#

Process.Start(@"C:\Games\Warcraft III\Warcraft III.exe","-window");

Posted 1-May-12 2:11am

OriginalGriff

Comments

Mossmyr 1-May-12 10:44am

Worked perfectly, thank you.

OriginalGriff 1-May-12 10:50am

You're welcome!