How to break array of string into words

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How to break array of string into words.
Example code:
$sample=array('Field name email is required','email must be valid address','password is required');
?>
I want to break each element of array.

For example the first element is break into 5 parts.How can i do that.

I tried.But i am not getting solution.

This is my code:

PHP

$sample=array('Field name email is required','email must be valid address','password is required');
$count=0;
for($i=0;$i<sizeof($sample);$i++){
    echo $sample[$i]."<br>";
    $a=$sample[$i];
    $arr= explode(' ',"$sample[$i]")."<br>";
    for($j=0;$j<sizeof($arr);$j++){
         echo $arr[$i]."<br>";
         //echo $count++;
        }
    }
    //echo sizeof($arr[$j]);
    print_r($arr);

?>

Posted 2-May-12 1:38am

DeepthiTanguturi

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Loke.mysore · Answer 1 · 2012-05-02T01:49:00

you update this code.

PHP

for ($i = 0; $i < sizeof($sample); $i++) {
    echo $sample[$i] . "<br>";
    $a = $sample[$i];
    $arr = explode(" ", "$sample[$i]");
    print_r($arr);
    for ($j = 0; $j < sizeof($arr); $j++) {
	echo $arr[$j] . "<br>";
	//echo $count++;
    }
}

i think this line will not work as u expected

PHP

$arr= explode(' ',"$sample[$i]")."<br>";

if we append "
" $arr will become a string variable , and it will not be an array.

DeepthiTanguturi · Answer 2 · 2012-05-02T02:35:00

PHP

$sample=array('Field name email is required','email must be valid address','password is required');
$count=0;
$mail="email";
for($i=0;$i<sizeof($sample);$i++){
    echo $sample[$i]."<br>";
    //$a=str_split($sample[$i],"");
    $chars = preg_split('/ /', $sample[$i]);
    //print_r($chars);
    if(array_search("$mail",$chars)){
    echo $sample[$i]."<br>";
    }
}

?>

How to break array of string into words

2 solutions

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