Split byte into 8 numbers

See more:

C++

C

Hello, is it possible to store 8 integers in range 0 - 31 in single byte?
I understand how to split one 32 bit integer into 4 bytes using bit shifting,
but I don't know if the same is possible with single byte.
One byte can hold 1 number up to 255. In case of 2 numbers,
I a assume they could be up to 127... in case of 8, looks like up to 31
should be real.

Or am I completely wrong and this is not possible?

I would like to have something like:

int getAt(int pos, byte b) // pos is 0 - 7
{
   // extraction code
}

void setAt(int pos, byte & b) // pos is 0 - 7
{
   // insertion code
}

What I have tried:

I have tied only to search on the web and shifting like b >> 1, but without luck.