Upload images in windows application

1. use openfiledialog to ask the file from the user.
2. filter the openfiledialog to accept images only.
3. Use File.Copy function to copy file from openfiledialog opened filepath to your chosen destination path.

I think the better option to storing image is to convert image to byte[] then store it in Database
Open a File First

byte[] big;
private void button7_Click(object sender, EventArgs e)
        {
             OpenFD.Title = "Select Files";
            OpenFD.Filter = "Jpg|*.jpg|Jpge|*.jpge|Gif|*.gif";
            OpenFD.FileName = null;
            string fileName;
            if (OpenFD.ShowDialog() != DialogResult.Cancel)
            {
                querybuilder qu = new querybuilder();
                fileName = OpenFD.FileName;
                Object refmissing = System.Reflection.Missing.Value;
                try
                {
                     // show it to picturebox
                    pictureBox2.Load(fileName);
                     // Here get_image is a function and Big is the byte[] type
                    big = get_image(fileName);
                }
                catch (Exception ex)
                {
                    MessageBox.Show("Error" + ex.Message.ToString());
                }
            }
        }

get_image function is below

public byte[] get_image(string filePath)
        {
            FileStream stream = new FileStream(filePath, FileMode.Open, FileAccess.Read);
            BinaryReader reader = new BinaryReader(stream);
            byte[] photo = reader.ReadBytes((int)stream.Length);
            reader.Close();
            stream.Close();

            return photo;
        }

And now make sql query

string sqlquery="insert into Tablename(id,image) values(1,@big)";
SqlParameter param = new SqlParameter("@big", SqlDbType.Binary);
    param.Value = big;

Note:- Create Sqlcommand self I didn't include it in that solution

private void cmdBrowser_Click(object sender, EventArgs e)
        {
            OpenFileDialog fileOpen = new OpenFileDialog();
            fileOpen.Title = "Open Image file";
            fileOpen.Filter = "JPG Files (*.jpg)| *.jpg";

            if (fileOpen.ShowDialog() == DialogResult.OK)
            {
                picImage.Image = Image.FromFile(fileOpen.FileName);
            }
            fileOpen.Dispose();
        }

make on button click on windows application.