how to generate randomly coupon number which are 6 digit

Question

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My dear friends ..I want to generate Alphanumeric 6 digit coupon number.
Can you solve my problem..
Please specify me clearly step by step..
I am waiting your answers..
Thanks!

Posted 16-Aug-12 23:18pm

Jitendra Ballia

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Comments

I.explore.code 17-Aug-12 5:22am

what have you tried yourself? this is not a place where people will do your work for you without you telling them what approaches have you already tried that hasn't worked.

marcelinha 13-May-15 14:52pm

why don't u shut ur mouth and help the guy?

3 solutions

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Manas Bhardwaj · Accepted Answer · 2012-08-16T23:24:00

Solution 1

Something like this:

C#

var chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";
var stringChars = new char[6];
var random = new Random();

for (int i = 0; i < stringChars.Length; i++)
{
    stringChars[i] = chars[random.Next(chars.Length)];
}

var finalString = new String(stringChars);

Read more about Random here:
http://msdn.microsoft.com/en-us/library/system.random.aspx

Posted 16-Aug-12 23:24pm

Manas Bhardwaj

Updated 16-Aug-12 23:31pm

v2

Comments

I.explore.code 17-Aug-12 5:34am

you guys are not exactly helping him. If he had even bothered to use his imagination and used Visual Studio Intellisense for the word "Random", he wouldn't be asking this question here.

marcelinha 13-May-15 14:54pm

again, why don't u shut up... and go f*** urself

Santhosh Kumar Jayaraman · Accepted Answer · 2012-08-16T23:28:00

Solution 2

C#

static void Main(string[] args)
        {
            string chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
            Random random = new Random();
            string result = new string(
                Enumerable.Repeat(chars, 8)
                          .Select(s => s[random.Next(s.Length)])
                          .ToArray());



        }

Posted 16-Aug-12 23:28pm

Santhosh Kumar Jayaraman

Updated 16-Aug-12 23:29pm

v2

Comments

I.explore.code 17-Aug-12 5:34am

you guys are not exactly helping him. If he had even bothered to use his imagination and used Visual Studio Intellisense for the word "Random", he wouldn't be asking this question here.

Code-Hunt · Accepted Answer · 2012-08-16T23:39:00

VB

Function Password_GenPass( nNoChars, sValidChars )
    ' nNoChars = length of generated password
    ' sValidChars = valid characters. If zerolength-string
     '   ( "" ) then
    '     default is used: A-Z AND a-z AND 0-9

    Const szDefault = "abcdefghijklmnopqrstuvxyzABCDEFGHIJKLMNOPQRSTUVXYZ0123456789"
    Dim nCount
    Dim sRet
    Dim nNumber
    Dim nLength

    Randomize 'init random

    If sValidChars = "" Then
        sValidChars = szDefault
    End If
    nLength = Len( sValidChars )

    For nCount = 1 To nNoChars
        nNumber = Int((nLength * Rnd) + 1)
        sRet = sRet & Mid( sValidChars, nNumber, 1 )
    Next
    Password_GenPass = sRet
    Password_GenPass( 6, "" ) = & pwd &
End Function

how to generate randomly coupon number which are 6 digit

3 solutions

Solution 1

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Solution 3

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