how to check last bit of byte is one

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I am having:

C#

byte[] buffer;
if((buffer[6])&(0x01))
{

}

I want to check the last bit in the 6th byte should be one so I am applying this but it throws me error: Cannot implicitly convert type 'int' to 'bool'.

Posted 13-Sep-12 6:24am

Member 9092048

Updated 13-Sep-12 6:28am

Sandeep Mewara

v2

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4 solutions

Solution 3

hello,

Try this:

C#

byte[] teste = new byte[3];
teste[0] = 0x01;
teste[1] = 0x02;
teste[2] = 0x03;

if (teste[2].Equals(0x03))
{
}
else
{
}

Posted 13-Sep-12 7:40am

ernesto fazolo

Solution 4

The problem is that your if statement is computing a numeric value with the bit-wise AND operator. c# does not implicitly convert integer zero/non-zero to boolean false/true.
Just compare the result of the AND against zero:

C#

if((buffer[6] & 0x01) != 0)
{
  // low-order bit is set
}

If you needed to check for multiple bits at the same time, compare against the bitmask:

C#

if((buffer[6] & 0x81) == 0x81)
{
  // both highest-order and low-order bits (binary: 10000001) are set
}

Posted 13-Sep-12 13:35pm

Matt T Heffron

Solution 2

If I am understanding your question/statement correctly, try this:

C#

byte[] buffer;
if (buffer[6].ToString().EndsWith("1"))
{
  //do stuff
}

Make sure your byte array actully has items in it.

Posted 13-Sep-12 6:38am

Richard C Bishop

Comments

Matt T Heffron 13-Sep-12 19:26pm

What makes you think the last character of the decimal representation of the value in buffer[6] is the character '1' when the low bit of the value is set?

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Sandeep Mewara · Accepted Answer · 2012-09-13T06:30:00

Solution 1

Cannot implicitly convert type 'int' to 'bool'.
Looks like your expression in the IF statement is not evaluating as a boolean value. Probably a wrong '&' operator?

C#

byte[] buffer;
byte one = 1 ;
if((buffer[6])== one)

Or:
Use MSDN: Byte.CompareTo Method (Byte)
[^]

C#

if(one.CompareTo(buffer[6]))
{
}

Posted 13-Sep-12 6:30am

Sandeep Mewara

Updated 13-Sep-12 6:33am

v2

Comments

Kuthuparakkal 13-Sep-12 21:16pm

my 5+

Matt T Heffron 19-Oct-12 21:16pm

This doesn't do what OP stated as the problem.
Checking *the low-order bit* of buffer[6] is 1,
not: checking if buffer[6] == 1
(aside: buffer[6] is actually the 7th byte)