split a field value in sql

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SQL-Server-2005

I wanna split a field value(seperated by semicolon) and save it in an array
Eg :

189;217;189;199;

And help me to retrieve it one by one and save on a temporary table
Like
row_num--value
---1-------189
---2-------217
---3-------189
---4-------199

Posted 4-Nov-12 18:16pm

Nimisha Mary John

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3 solutions

Solution 2

Try this ...

SQL

DECLARE @param VARCHAR(MAX) = '189;217;189;199;';
SET @param = SUBSTRING(@param,0,LEN(@param))

DECLARE @Xparam XML;

SELECT @Xparam = CAST('<i>' + REPLACE(@param,';','</i><i>') + '</i>' AS XML)
SELECT ROW_NUMBER() OVER( ORDER BY x.i.value('.','INT')) ROWNUM,x.i.value('.','INT') FROM @Xparam.nodes('//i') x(i)

Thank you

Posted 4-Nov-12 18:46pm

damodara naidu betha

Solution 1

Mr. goo0gle search gave me

An Easy But Effective Way to Split a String using Transact-SQL[^]

Posted 4-Nov-12 18:19pm

saud_a_k

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Aarti Meswania · Accepted Answer · 2012-11-04T18:53:00

Create this function in your database

SQL

set ANSI_NULLS ON
set QUOTED_IDENTIFIER ON
GO
CREATE FUNCTION [dbo].[ParseValues]
(@String varchar(8000), @Delimiter varchar(10) )
RETURNS @RESULTS TABLE (ID int identity(1,1), Val varchar(50))
AS
BEGIN
    DECLARE @Value varchar(100)
    WHILE @String is not null
    BEGIN
        SELECT @Value=CASE WHEN PATINDEX('%'+@Delimiter+'%',@String) >0 THEN LEFT(@String,PATINDEX('%'+@Delimiter+'%',@String)-1) ELSE @String END, @String=CASE WHEN PATINDEX('%'+@Delimiter+'%',@String) >0 THEN SUBSTRING(@String,PATINDEX('%'+@Delimiter+'%',@String)+LEN(@Delimiter),LEN(@String)) ELSE NULL END
        INSERT INTO @RESULTS (Val)
        SELECT @Value
    END
    RETURN
END

Now, call this function like below,

SQL

select * from dbo.parsevalues('189;217;189;199;',';') where val<>''

Happy Coding!
:)