How do I find the correct node among many nodes that matches variable value (strcourtncic) value? )

Question

0.00/5 (No votes)

See more:

I am really stuck on this one even though it seems like what I want is simple.
I have ObjXmlSimpleTypeDoc object which have two EnumerationValue nodes. Each of EnumerationValue have child nodes.

I want to find the correct EnumerationValue. To find the correct EnumerationValue node, I use a variable strCourtNCIC. If the value in strCourtNCIC (in this case MN010015J. This value can be some other value) matches a EnumerationValue@code, that is the EnumerationValue node I need.
For this question strCourtNCIC hold a value MN010015J.

How do I do this in VB.NET? My VB.NET code returns Nothing for objXmlEnumerationValueNode even though I am expecting to see the node with @code = MN010015J

Here is the objXmlSimpleTypeDoc object where I need to find EnumerationValue with @code = strCourtNCIC (MN010015J)

XML

<SimpleTypeCompanion enumerates="CourtLocationTextType">
	<EnumerationValue code="MN010015J">
		<Text>Emily County</Text>
		<AssociatedValue type="MNCISNodeID">
			<Text>111</Text>
		</AssociatedValue>
		<AssociatedValue type="CountyName">
			<Text>Emily</Text>
		</AssociatedValue>
		<AssociatedValue type="PhoneNumber">
			<Text>724-820-7123</Text>
		</AssociatedValue>
	</EnumerationValue>
	<EnumerationValue code="DC19DAKDC">
		<Text>Pope County</Text>
		<AssociatedValue type="MNCISNodeID">
			<Text>112</Text>
		</AssociatedValue>
		<AssociatedValue type="CountyName">
			<Text>Pope</Text>
		</AssociatedValue>
	</EnumerationValue>
</SimpleTypeCompanion>

What I have tried:

Here is the VB.NET code that I need help with to just get the correct EnumerationValue that matches strCourtNCIC (MN010015J).

VB

'CourtNCIC 
strCourtNCIC = objXmlMNCISData.DocumentElement.SelectSingleNode("Case/Court/CourtNCIC").InnerText
'Access the CourtLocationTextType simple type. 
objXmlSimpleTypeDoc = Msc.Integration.CourtXml.Library.v4.SimpleType.GetCompanionFile("CourtLocationTextType")

'Get the correct EnumerationValue node that has @code =MN010015J string value
objXmlEnumerationValueNode = objXmlSimpleTypeDoc.SelectSingleNode("/SimpleTypeCompanion/EnumerationValue[@code=" + strCourtORI + "]/@code")

Posted 12-Aug-19 6:03am

Member 11403304

Updated 13-Aug-19 10:39am

v2

Add a Solution

2 solutions

Solution 2

Another way is to use XDocument class[^]:

VB.NET

Dim xcontent As String = "<SimpleTypeCompanion enumerates='CourtLocationTextType'>
	<EnumerationValue code='MN010015J'>
		<Text>Emily County</Text>
		<AssociatedValue type='MNCISNodeID'>
			<Text>111</Text>
		</AssociatedValue>
		<AssociatedValue type='CountyName'>
			<Text>Emily</Text>
		</AssociatedValue>
		<AssociatedValue type='PhoneNumber'>
			<Text>724-820-7123</Text>
		</AssociatedValue>
	</EnumerationValue>
	<EnumerationValue code='DC19DAKDC'>
		<Text>Pope County</Text>
		<AssociatedValue type='MNCISNodeID'>
			<Text>112</Text>
		</AssociatedValue>
		<AssociatedValue type='CountyName'>
			<Text>Pope</Text>
		</AssociatedValue>
	</EnumerationValue>
</SimpleTypeCompanion>"

Dim strCourtORI As String = "MN010015J"

Dim xdoc As XDocument = XDocument.Parse(xcontent)
Dim result = xdoc.Descendants() _
	.Where(Function(x) x.Name="EnumerationValue" AndAlso x.Attribute("code").Value = strCourtORI) _
	.FirstOrDefault()
'done!

Posted 13-Aug-19 10:39am

Maciej Los

Comments

Richard Deeming 14-Aug-19 4:22am

FYI, that could fail with a NullReferenceException if there was an EnumerationValue element without a code attribute.

The explicit cast operators which cast to a reference type or a nullable value type will not fail if the element or attribute is null, so it might be safer to use that.

.Where(Function(x) x.Name = "EnumerationValue" AndAlso CStr(x.Attribute("code")) = strCourtORI) _

Maciej Los 14-Aug-19 5:44am

Good point, Richard. Thank you.

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Richard Deeming · Accepted Answer · 2019-08-13T05:07:00

Solution 1

You haven't shown us where you initialize the strCourtORI variable. But looking at your data, the most likely problem is that you're missing quotes around the value:

VB.NET

objXmlEnumerationValueNode = objXmlSimpleTypeDoc.SelectSingleNode("/SimpleTypeCompanion/EnumerationValue[@code='" + strCourtORI + "']")

Also note that you were trying to select the attribute itself, rather than the EnumerationValue node.

Posted 13-Aug-19 5:07am

Richard Deeming

Comments

Member 11403304 13-Aug-19 12:16pm

Hi Richard, you have solved my issue. Yes I was missing the single quotes around the value. You have stopped all the pain I went through for the last many days. Something so simple yet so difficult to figure out!

Maciej Los 13-Aug-19 16:36pm

5ed!