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How do I generate random string using the characters of length(len)? in C

void gen_random(char *s, const int len)
    char charset[] = "0123456789!\"#$%&'()*+-/. ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";

What I have tried:

I tried doing char randomString
Updated 6-Sep-19 5:37am
Patrice T 6-Sep-19 9:26am
The question makes no sense.
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Solution 1

KarstenK 7-Sep-19 15:29pm
RTFM - the epic answer.

scnr ;-)
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Solution 2

Richard has given you the link you need: now all you have to do is use it.
How? Simple: You function gets two parameters, a pointer and a
Use a loop that iterates len times, and inside the loop call the rand function. That returns an integer value, so use the % operator (which returns a remainder) to give you a value between 0 and the length of charset minus one. That is your random index into charset - so fetch the character at the index, and add it to the output and increment the pointer.

You may need to add a null value after the loop if it's to be treated as a string, but that will depend on the defintion of your function. If there aren't enough characters in the memory area passed to your function, don't add it!
k5054 6-Sep-19 14:40pm
Don't forget about srand(). Note that the code given on the MS Docs link does have one issue: because it uses time() to seed rand, it can produce identical results if the program is run more than once within the same second. In general, there's probably a pretty small chance of that happening, but it is something to be aware of, should circumstances require.
Rick York 6-Sep-19 23:47pm
If that matters you could use timeGetTime() and get milliseconds. The chance of the program starting twice in the same millisecond seems exceedingly remote to me.

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